Question

[OoO Hoàng Tử Lạnh Lùng OoO]

Giúp với giải thích đầy đủ nha !! Mik sẽ tick ..

bài 1 :

H = 3/1.5 + 3/5.9 + 3/9.13 + ... + 3/33.37

Tính H hộ nha !!

Bài 2 :

1/3.5 + 1/5.7 + 1/7.9 + ... + 1/ (2x + 1 ) . ( 2x + 3 ) = 15/93 

Giải đầy đủ hộ nha !

Answer 1

[Thanh Tùng DZ]

2.

\(\frac{1}{3.5}+\frac{1}{5.7}+\frac{1}{7.9}+...+\frac{1}{\left(2x+1\right).\left(2x+3\right)}=\frac{15}{93}\)

\(\Rightarrow\frac{1}{2}.\left(\frac{1}{3}-\frac{1}{5}\right)+\frac{1}{2}.\left(\frac{1}{5}-\frac{1}{7}\right)+\frac{1}{2}.\left(\frac{1}{7}-\frac{1}{9}\right)+...+\frac{1}{2}.\left(\frac{1}{2x+1}-\frac{1}{2x+3}\right)=\frac{15}{93}\)

\(\Rightarrow\frac{1}{2}.\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+...+\frac{1}{2x+1}-\frac{1}{2x+3}\right)=\frac{15}{93}\)

\(\Rightarrow\frac{1}{2}.\left(\frac{1}{3}-\frac{1}{2x+3}\right)=\frac{15}{93}\)

\(\Rightarrow\frac{1}{3}-\frac{1}{2x+3}=\frac{15}{93}:\frac{1}{2}\)

\(\Rightarrow\frac{1}{3}-\frac{1}{2x+3}=\frac{10}{31}\)

\(\Rightarrow\frac{1}{2x+3}=\frac{1}{3}-\frac{10}{31}\)

\(\Rightarrow\frac{1}{2x+3}=\frac{1}{93}\)

\(\Rightarrow\)2x + 3 = 93

\(\Rightarrow\)2x = 93 - 3

\(\Rightarrow\)2x = 90

\(\Rightarrow\)x = 90 : 2 = 45

Answer 2

[ST]

\(H=\frac{3}{1.5}+\frac{3}{5.9}+\frac{3}{9.13}+...+\frac{3}{33.37}\)

= \(\frac{3}{4}\left(1-\frac{1}{5}+\frac{1}{5}-\frac{1}{9}+\frac{1}{9}-\frac{1}{13}+...+\frac{1}{33}-\frac{1}{37}\right)\)

= \(\frac{3}{4}\left(1-\frac{1}{37}\right)\)

= \(\frac{3}{4}.\frac{36}{37}=\frac{27}{37}\)