Question

[NgPhuongThao]

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Answer 1

[Vô danh]

\(a,3x+17=-5\\ \Rightarrow3x=-22\\ \Rightarrow x=-\dfrac{22}{3}\\ b,\dfrac{-5}{8}=\dfrac{x}{16}\\ \Rightarrow x=\dfrac{-5}{8}.16\\ \Rightarrow x=-10\\ c,\dfrac{4}{9}+\dfrac{7}{3}:x=\dfrac{1}{5}\\ \Rightarrow\dfrac{7}{3}:x=-\dfrac{11}{45}\\ \Rightarrow x=-\dfrac{105}{11}\)

Answer 2

[Nguyễn Tân Vương]

\(a)3.x+17=-5\)

\(3.x\)         \(=\left(-5\right)-170=-22\)

  \(x\)          \(=\left(-22\right)\div3\)

  \(x\)          \(=\dfrac{-22}{3}\)

\(b)\dfrac{-5}{8}=\dfrac{x}{16}\)

\(\Rightarrow x=\dfrac{\left(-5\right)\times16}{8}=\dfrac{-80}{8}=-10\)

\(c)\dfrac{4}{9}+\dfrac{7}{3}:x=\dfrac{1}{5}\)

           \(\dfrac{7}{3}:x=\dfrac{1}{5}-\dfrac{4}{9}\)

           \(\dfrac{7}{3}:x=\dfrac{1}{5}+\left(\dfrac{-4}{9}\right)=\dfrac{9}{45}+\left(\dfrac{-20}{45}\right)=\dfrac{-11}{45}\)

                 \(x=\dfrac{7}{3}:\left(\dfrac{-11}{45}\right)=\dfrac{7}{3}\times\left(\dfrac{-45}{11}\right)\)

                 \(x=\dfrac{-315}{33}=\dfrac{-105}{11}\)