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Ta có:
\(3^4+3^5\)
\(=3^4.\left(1+3\right)\)
\(=3^4.4⋮4\left(\text{đ}pcm\right)\)
82 x 324 = (23)2 x (25)4 = 26 x 220=226
273 x 94 x243 = 39 x 38x35=322
643 : 163 =218 : 212 = 26
513:1254 = 513 : 512= 5
Đặt \(A=\frac{3^2\cdot4^2\cdot2^{32}}{11\cdot2^{13}\cdot4^{11}-16^9}\)
\(A=\frac{3^2\cdot\left(2^2\right)^2\cdot2^{32}}{11\cdot2^{13}\cdot\left(2^2\right)^{11}-16^9}\)
\(A=\frac{3^2\cdot2^4\cdot2^{32}}{11\cdot2^{13}\cdot2^{22}-16^9}=\frac{3^2\cdot2^{36}}{11\cdot2^{35}-\left(2^4\right)^9}\)
\(A=\frac{3^2\cdot2^{36}}{11\cdot2^{35}-2^{36}}\)
\(A=\frac{3^2\cdot2^{36}}{11\cdot2^{35}-2\cdot2^{35}}\)
\(A=\frac{3^2\cdot2^{36}}{\left(11-2\right)\cdot2^{35}}=\frac{9\cdot2^{36}}{9\cdot2^{35}}=\frac{2^{36}}{2^{35}}=2\)
Bài làm:
\(\frac{3^2.4^2.2^{32}}{11.2^{13}.4^{11}-16^9}\)
\(=\frac{3^2.\left(2^2\right)^2.2^{32}}{11.2^{13}.\left(2^2\right)^{11}-\left(2^4\right)^9}\)
\(=\frac{3^2.2^4.2^{32}}{11.2^{13}.2^{22}-2^{36}}\)
\(=\frac{3^2.2^{36}}{11.2^{35}-2^{36}}\)
\(=\frac{3^2.2^{36}}{\left(11-2\right).2^{35}}\)
\(=\frac{9.2^{36}}{9.2^{35}}\)
\(=2\)
Học tốt
1. Ta có: \(16^{30}=\left(2^4\right)^{30}=2^{120}\)
Mà \(2^{120}< 3^{120}< 3^{121}\)
\(\Rightarrow2^{120}< 3^{121}\)
\(\Rightarrow16^{30}< 3^{121}\)
2. Ta có: \(5^{22}=5^{2.11}=\left(5^2\right)^{11}=25^{11}\)
Vì 25 < 64 nên \(25^{11}< 64^{29}\)
Vậy \(5^{22}< 64^{29}\)
3. Ta có: \(8^{120}=\left(2^3\right)^{120}=2^{360}\)
\(64^{29}=\left(2^6\right)^{29}=2^{174}\)
Vì 360 < 174 nên \(2^{360}< 2^{174}\)
Vậy \(8^{120}>64^{29}\)
4. Ta có: \(333^{444}=\left(333^4\right)^{111}\) \(=\left(111^4.3^4\right)^{111}=\left(111^4.81\right)^{111}\)
\(444^{333}=\left(444^3\right)^{111}\) \(=\left(111^3.4^3\right)^{111}=\left(111^3.64\right)^{111}\)
Vì \(111^4.81>111^3.64\) nên \(\left(111^4.81\right)^{111}>\left(111^3.64\right)^{111}\)
Vậy \(333^{444}>444^{333}\)
ban tra loi hoi cham , sang nay thay mk giai roi . Nhung ma mk se tick cho ban nhe !
( 3x - 24 ) . 73 = 2 . 74
( 3x - 24 ) = 2 . 74 : 73
( 3x - 24 ) = 2 . 7
3x - 24 = 14
3x = 14 + 24
3x = 14 + 16
3x = 30
x = 10
- Hok T -
Bổ sung đề bài : Tính
\(64^3.4^8.16^4=\left(2^6\right)^3.\left(2^2\right)^8.\left(2^4\right)^4\)
\(=2^{18}.2^{16}.2^{16}=2^{50}\)