Câu hỏi của nguyễn sunny ly

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Giúp mk với ạ, cảm ơn trước

Nguyễn Lê Phước Thịnh · Accepted Answer

8) Ta có: $x+\dfrac{3}{2}=-\dfrac{5}{3}$$\Leftrightarrow x=-\dfrac{5}{3}-\dfrac{3}{2}=\dfrac{-10}{6}-\dfrac{9}{6}$hay $x=-\dfrac{19}{6}$Vậy: $x=-\dfrac{19}{6}$10) Ta có: $\left|x-\dfrac{1}{2}\right|+75\%=\dfrac{9}{10}$$\Leftrightarrow\left|x-\dfrac{1}{2}\right|=\dfrac{3}{20}$$\Leftrightarrow\left[{}\begin{matrix}x-\dfrac{1}{2}=\dfrac{3}{20}\x-\dfrac{1}{2}=-\dfrac{3}{20}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{13}{20}\x=\dfrac{7}{20}\end{matrix}\right.$Vậy: $S=\left\{\dfrac{13}{20};\dfrac{7}{20}\right\}$11) Ta có: $x+\dfrac{2}{3}=-\dfrac{1}{2}$nên $x=-\dfrac{1}{2}-\dfrac{2}{3}=\dfrac{-3}{6}-\dfrac{4}{6}$hay $x=-\dfrac{7}{6}$Vậy: $S=\left\{-\dfrac{7}{6}\right\}$Câu trả lời: 8) Ta có: $x+\dfrac{3}{2}=-\dfrac{5}{3}$$\Leftrightarrow x=-\dfrac{5}{3}-\dfrac{3}{2}=\dfrac{-10}{6}-\dfrac{9}{6}$hay $x=-\dfrac{19}{6}$Vậy: $x=-\dfrac{19}{6}$10) Ta có: $\left|x-\dfrac{1}{2}\right|+75\%=\dfrac{9}{10}$$\Leftrightarrow\left|x-\dfrac{1}{2}\right|=\dfrac{3}{20}$$\Leftrightarrow\left[{}\begin{matrix}x-\dfrac{1}{2}=\dfrac{3}{20}\x-\dfrac{1}{2}=-\dfrac{3}{20}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{13}{20}\x=\dfrac{7}{20}\end{matrix}\right.$Vậy: $S=\left\{\dfrac{13}{20};\dfrac{7}{20}\right\}$11) Ta có: $x+\dfrac{2}{3}=-\dfrac{1}{2}$nên $x=-\dfrac{1}{2}-\dfrac{2}{3}=\dfrac{-3}{6}-\dfrac{4}{6}$hay $x=-\dfrac{7}{6}$Vậy: $S=\left\{-\dfrac{7}{6}\right\}$

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