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\(a,-12.\left(x-5\right)+7.\left(-x+3\right)=5\)
\(-12x+60-7x+21=5\)
\(-19x+81=5\)
\(-19x=5-81\)
\(-19x=-76\)
\(x=4\)
\(b,30.\left(x+2\right)-6.\left(x-5\right)-24.x=100\)
\(30x+60-6x+30-24x=100\)
\(0x+90=100\)
\(0x=100-90\)
\(0x=10\)
=> ko có giá trị nào thõa mãn x
1) \(\frac{7}{3}+\frac{1}{2}-\left(-\frac{3}{70}\right)=\frac{7}{3}+\frac{1}{2}+\frac{3}{70}=\frac{490}{210}+\frac{105}{210}+\frac{9}{210}=\frac{604}{210}=\frac{302}{105}\)
2) \(\frac{5}{12}-\left(\frac{3}{-16}\right)+\frac{3}{4}=\frac{5}{12}+\frac{3}{16}+\frac{3}{4}=\frac{20}{48}+\frac{9}{48}+\frac{36}{48}=\frac{65}{48}\)
\(-12\left(x-5\right)+7\left(3-x\right)=5\)
\(\Rightarrow-12x+60+21-7x=5\)
\(\Rightarrow-19x+81=5\)
\(\Rightarrow-19x=-76\)
\(\Rightarrow x=4\)
Vậy \(x=4\)
12-12+11+10-9+8-7+5-4+3+2-1
=-(12+12-11-10)-(9-8+7-5)+(4-3-2+1)
=(-3)-3+0
=(-6)
Chúc bn học tốt
=> 7x/12 + 5x/12 = 5/8 +3/8
=> 12x/12 =8/8=1
12x =12
x= 12:12 =1
\(a,\frac{21}{36}.\frac{5}{2}-\frac{7}{12}.\frac{2}{7}+\left(2018-2019\right)^0\)
=\(\frac{7}{12}.\frac{5}{2}-\frac{7}{12}.\frac{2}{7}+\left(-1\right)\)
= \(\frac{7}{12}.\left(\frac{5}{2}+\frac{2}{7}\right)+\left(-1\right)\)
=\(\frac{7}{12}.\frac{39}{14}+\left(-1\right)\)
=\(\frac{13}{8}+\left(-1\right)\)
= \(\frac{5}{8}\)
\(b,-12\frac{1}{3}-\frac{5}{7}+7\frac{1}{3}+1\frac{5}{7}+1^{2019}\)
=\(-\frac{37}{3}+\frac{-5}{7}+\frac{22}{3}+\frac{12}{7}+1\)
=\(\left(\frac{-37+22}{3}\right)+\left(\frac{-5+12}{7}\right)+=1\)
= \(-5+1+1\)
=\(-3\)
Ta có : 1/3 + 5/8 - 7/12 = 8/24 + 15/34 - 14/24
= 23/24 - 14/24
= 23/24 + -14/24
= 9/24
= 3/8