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\(\frac{3^6.45^4-15^{13}.5^{-9}}{27^4.25^3+45^6}\)=\(\frac{3^6.3^8.5^4-5^{13}.3^{13}.5^{-9}}{3^{12}.5^6+3^{12}.5^6}\)=\(\frac{3^{14}.5^4-5^4.3^{13}}{3^{12}.5^6+3^{12}.5^6}\)=\(\frac{3.1.}{1.5^2.}\)=\(\frac{3}{25}\)
Học tốt
#)Giải :
a)\(2^6.5^6=\left(2.5\right)^6=10^6\)
b)\(8^2.5^2=\left(8.5\right)^2=40^2\)
c)\(4^3.5^3=\left(4.5\right)^3=20^3\)
d)\(5^2.6^2.3^2=\left(5.6.2\right)^2=60^2\)
e)\(\frac{625^5}{25^8}=\frac{\left(25^2\right)^5}{25^8}=\frac{25^{10}}{25^8}=25^2\)
g)\(\frac{3^9}{7}.\frac{7^9}{3}=\frac{\left(3.7\right)^9}{7.3}=\frac{21^9}{21}=21^8\)
Bài làm
a) Ta có: \(\left(-\frac{3}{2}\right)^x=\frac{9}{4}\)
=>\(\left(-\frac{3}{2}\right)^x=\left(-\frac{3}{2}\right)^2\)
Vậy x = 2
b) Ta có: \(\left(-\frac{2}{3}\right)^x=-\frac{8}{27}\)
=> \(\left(-\frac{2}{3}\right)^x=\left(-\frac{2}{3}\right)^3\)
Vậy x = 3
# Học tốt #
a)\(\left(0,25^{10}\right).4^{10}.\sqrt{5^2-3^2}=\left(0,25.4\right)^{10}.\sqrt{25-9}=1^{10}.\sqrt{16}=1.4=4\)
b)\(\frac{\left(-3\right)^6.15^5+9^3.\left(-15\right)^6}{\left(-3\right)^{10}.5^5.2^3}=\frac{3^6.15^5+3^6.15^6}{3^{10}.5^5.2^3}=\frac{3^6.15^5.\left(1+15\right)}{3^{10}.5^5.2^3}\)\(=\frac{3^{11}.5^5.16}{3^{10}.5^5.2^3}=3.2=6\)
2)a)\(4-\left|x+\frac{2}{3}\right|=-1\Rightarrow\left|x+\frac{2}{3}\right|=5\Rightarrow\orbr{\begin{cases}x+\frac{2}{3}=5\\x+\frac{2}{3}=-5\end{cases}\Rightarrow}\orbr{\begin{cases}x=\frac{13}{3}\\x=\frac{-17}{3}\end{cases}}\)
b)\(\frac{x-2}{-9}=\frac{16}{2-x}\Rightarrow\left(x-2\right)^2=144\Rightarrow\orbr{\begin{cases}x-2=12\\x-2=-12\end{cases}\Rightarrow\orbr{\begin{cases}x=14\\x=-10\end{cases}}}\)
c)\(\frac{2}{3}x+\frac{1}{7}=\frac{5}{3}\Rightarrow\frac{2}{3}x=\frac{32}{21}\Rightarrow x=\frac{16}{7}\)
ta có
\(\frac{3^6.\left(3.5\right)^8}{\left(3.3\right)^7.5^9}\)= \(\frac{3^6.3^8.5^8}{3^7.3^7.5^9}\)= \(\frac{1}{5}\)
Đặt \(A=\frac{3^6.15^8}{9^7.5^9}\)
\(\Leftrightarrow A=\frac{3^6.\left(3.5\right)^8}{\left(3^2\right)^7.5^9}\)
\(\Leftrightarrow A=\frac{3^6.3^8.5^8}{3^{14}.5^9}\)
\(\Leftrightarrow A=\frac{3^{14}.5^8}{3^{14}.5^9}\)
\(\Leftrightarrow A=\frac{3^{14}}{3^{14}}.\frac{5^8}{5^9}\)
\(\Leftrightarrow A=1.\frac{1}{5}=\frac{1}{5}\)