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Số lần số học sinh cả lớp gấp số học sinh nam là :
28 : 7 = 4 (lần)
Đ/S : 4 lần
Mẹ Ba hơn em Ba số tuổi là: 32 - 6 = 26(tuổi)
Hiệu số tuổi của 2 người không thay đổi theo thời gian.
Khi tuổi em Ba bằng 1/3 tuổi mẹ Ba thì mẹ của Ba hơn em Ba là: 1 - 1/3 = 2/3
Tuổi em Ba khi đó là: 26 : 2 = 13(tuổi)
Vậy sau 7 năm nữa(13 - 6 = 7) thì tuổi em Ba bằng 1/3 tuổi mẹ Ba
lớp 3A có số học sinh giỏi bằng số học sinh cả lớp là:
7:35=\(\frac{7}{35}=\frac{1}{5}\)
Đáp số:\(\frac{1}{5}\)
Tick ủng hộ mình nha bạn
\(3a758\) : 9 dư 2 khi và chỉ khi 3 + a + 7 + 5 + 8 : 9 dư 2
(3 + 7 + 8) + 5 + a : 9 dư 2
18 + 5 + a : 9 dư 2
5 + a : 9 dư 2
vì a ≤ 9 ⇒ 5 + a ≤ 14 mà a + 5 : 9 dư 2 nên
a + 5 = 11
a = 11 - 5
a = 6
Vậy \(\overline{3a578}\) = 36578
Hiệu số tuổi của 2 mẹ con tôi là:
32 - 6 = 26 (tuổi)
vì mỗi năm mẹ và tôi sẽ tăng lên và hiệu này sẽ ko thay đổi :
Tuổi tôi lúc tuổi tôi bằng 1/3 tuổi mẹ là:
26 : ( 3 - 1) x 1 = 13 ( tuổi )
Vậy cần thêm số năm nữa để số tuổi tôi bằng 1/3 tuổi mẹ là:
13 - 6 = 7 ( năm )
đáp số.......
I. Nội qui tham gia "Giúp tôi giải toán"
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