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21 tháng 1 2022
\(P=\left(\dfrac{2x}{x+3}+\dfrac{x}{x-3}-\dfrac{3x^2+3}{x^2-9}\right):\left(\dfrac{2x-2}{x-3}-1\right)\)
\(\Rightarrow P=\dfrac{2x\left(x-3\right)+x\left(x+3\right)-\left(3x^2+3\right)}{\left(x+3\right)\left(x-3\right)}:\dfrac{2x-2-\left(x-3\right)}{x-3}\)
\(\Rightarrow P=\dfrac{2x^2-6x+x^2+3x-3x^2-3}{\left(x+3\right)\left(x-3\right)}:\dfrac{2x-2-x+3}{x-3}\)
\(\Rightarrow P=\dfrac{-3x-3}{\left(x+3\right)\left(x-3\right)}:\dfrac{x+1}{x-3}\)
\(\Rightarrow P=\dfrac{-3\left(x+1\right)}{\left(x+3\right)\left(x-3\right)}.\dfrac{x-3}{x+1}\)
\(\Rightarrow P=\dfrac{-3}{x+3}\)
KC
4
TM
18 tháng 1 2022
a. \(D=\left(\dfrac{x^2-3x}{x^2-9}-1\right):\left(\dfrac{9-x^2}{x^2+x-6}-\dfrac{x-3}{2-x}-\dfrac{x-2}{x+3}\right)\)
\(=\left[\dfrac{x\left(x-3\right)}{\left(x+3\right)\left(x-3\right)}-1\right]:\left[\dfrac{\left(3-x\right)\left(3+x\right)}{x^2-2x+3x-6}-\dfrac{x-3}{2-x}-\dfrac{x-2}{x+3}\right]\)
\(=\left(\dfrac{x}{x+3}-1\right):\left[\dfrac{\left(3-x\right)\left(3+x\right)}{x\left(x-2\right)+3\left(x-2\right)}-\dfrac{x-3}{2-x}-\dfrac{x-2}{x+3}\right]\)
\(=\left(\dfrac{x}{x+3}-\dfrac{x+3}{x+3}\right):\left[\dfrac{\left(3-x\right)\left(3+x\right)}{\left(x-2\right)\left(x+3\right)}-\dfrac{x-3}{2-x}-\dfrac{x-2}{x+3}\right]\)
\(=\dfrac{3}{x+3}:\left(\dfrac{3-x}{x-2}-\dfrac{3-x}{x-2}-\dfrac{x-2}{x+3}\right)\)
\(=\dfrac{3}{x+3}:\dfrac{x-2}{x+3}\)
\(=\dfrac{3\left(x+3\right)}{\left(x+3\right)\left(x-2\right)}=\dfrac{3}{x-2}\)
31 tháng 12 2018
\(56^2+44^2+2.44.56\)
\(=\left(56+44\right)^2\)
\(=100^2=10000\)
KC
1
AM
2
11 tháng 8 2021
b: Ta có: \(5\left(x-1\right)^2-\left(1-x\right)\)
\(=5\left(x-1\right)^2+\left(x-1\right)\)
\(=\left(x-1\right)\left(5x-5+1\right)\)
\(=\left(x-1\right)\left(5x-4\right)\)
11 tháng 8 2021
a: Ta có: \(5x^2-4xy-x^2y\)
\(=x\left(5x-4y-xy\right)\)
23 tháng 12 2021
e: \(E=\dfrac{x^2-9-x^2+4-x^2+9}{\left(x+3\right)\left(x-2\right)}\)
\(=\dfrac{x+2}{x+3}\)
a: \(A=\dfrac{4x^2+x^2-2x+1+x^2+2x+1}{\left(x-1\right)\left(x+1\right)}\)
\(=\dfrac{6x^2+2}{\left(x-1\right)\left(x+1\right)}\)
