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12 : {390 : [500 - (125 + 35 . 7)]}
= 12 : {390 : [500 - (125 + 245)]}
= 12 : [390 : (500 - 370)]
= 12 : (390 : 130)
= 12 : 3
= 4
12 : { 390 : [ 500 - ( 125 + 35. 7 ) ] }
= 12 : { 390 : [ 500 - ( 125 + 245 ) ] }
= 12 : { 390 : [ 500 - 370 ] }
= 12 : { 390 : 130 }
= 12 : 3
= 4
Bài 3:
a: \(x=\dfrac{1}{4}-\dfrac{2}{13}=\dfrac{13}{52}-\dfrac{8}{52}=\dfrac{5}{52}\)
b: \(\dfrac{x}{3}=\dfrac{2}{3}-\dfrac{1}{7}\)
nên \(x\cdot\dfrac{1}{3}=\dfrac{14}{21}-\dfrac{3}{21}=\dfrac{11}{21}\)
hay \(x=\dfrac{11}{21}:\dfrac{1}{3}=\dfrac{11}{7}\)
a: \(\left(-154\right)\cdot\left(-235\right)+154\cdot\left(-35\right)\)
\(=154\cdot235-154\cdot35\)
\(=154\left(235-35\right)=154\cdot200=30800\)
b: \(\left(-12\right)\left(7-72\right)-25\cdot\left(55-43\right)\)
\(=12\cdot65-25\cdot12\)
\(=12\left(65-25\right)=12\cdot40=480\)
c: \(15\cdot\left(-236\right)+\left(-15\right)\cdot\left(-235\right)\)
\(=15\left(-236\right)+15\cdot235\)
\(=15\left(-236+235\right)=-15\cdot1=-15\)
d: \(237\cdot\left(-28\right)+28\cdot137\)
\(=28\left(137-237\right)\)
\(=28\cdot\left(-100\right)=-2800\)
\(\left(2x-15\right)^5=\left(2x-15\right)^3\)
\(\Rightarrow\left(2x-15\right)^5-\left(2x-15\right)^3=0\)
\(\Rightarrow\left(2x-15\right)^3\left[\left(2x-15\right)^2-1\right]=0\)
\(\Rightarrow\left(2x-15\right)^3\left(2x-15-1\right)\left(2x-15+1\right)=0\)
\(\Rightarrow\left(2x-15\right)^3\left(2x-16\right)\left(2x-14\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}2x-15=0\\2x-16=0\\2x-14=0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}2x=15\\2x=16\\2x=14\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{15}{2}\\x=8\\x=7\end{matrix}\right.\)
- 12 + 3(-x + 7) = -12 -3x - 21 = -3x - 33 = -3(x + 11)