Question

[Nguyễn Tấn Phát]

Giải pt:

\(1.\text{ }\hept{\begin{cases}x+2y=5\\3x-y=1\end{cases}}\)

\(2.\text{ }\hept{\begin{cases}9y-2x=10\\4x-2y=12\end{cases}}\)

\(3,\text{ }\hept{\begin{cases}\sqrt{4x-y}=a\\8x-2y=2a^2\end{cases}}\text{ }\left(a\ge0\right)\)

Answer 1

[ღ๖ۣۜLinh's ๖ۣۜLinh'sღ] ★we are one★]

\(1,\hept{\begin{cases}x+2y=5\\3x-y=1\end{cases}\Leftrightarrow}\hept{\begin{cases}3x+6y=15\\3x-y=1\end{cases}\Leftrightarrow}\hept{\begin{cases}x=1\\y=2\end{cases}}\)

\(2,\hept{\begin{cases}9y-2x=10\\4x-2y=12\end{cases}\Leftrightarrow}\hept{\begin{cases}9y-2x=10\\2x-y=6\end{cases}\Leftrightarrow}\hept{\begin{cases}x=4\\y=2\end{cases}}\)

\(3,\hept{\begin{cases}\sqrt{4x-y}=a\\8x-2y=2a^2\end{cases}\Leftrightarrow\hept{\begin{cases}8x-2y=2a^2\\8x-2y=2a^2\end{cases}}\Leftrightarrow khong}cogiatri\)

Answer 2

[Nguyễn Linh Chi]

3)\(\hept{\begin{cases}8x-2y=2a^2\\8x-2y=2a^2\end{cases}}\Leftrightarrow8x-2y=2a^2\) có vô số nghiệm em nhé!