Question

[16 Huỳnh Tuấn Kiệt]

Giải phương trình:

\(\sqrt{18x-27}-\dfrac{1}{2}\sqrt{32x-48}+3\sqrt{\dfrac{16x-24}{2}}=1\)

Answer 1

[Nguyễn Hoàng Minh]

\(ĐK:x\ge\dfrac{3}{2}\\ PT\Leftrightarrow3\sqrt{2x-3}-2\sqrt{2x-3}+6\sqrt{2x-3}=1\\ \Leftrightarrow7\sqrt{2x-3}=1\\ \Leftrightarrow\sqrt{2x-3}=\dfrac{1}{7}\\ \Leftrightarrow2x-3=\dfrac{1}{49}\Leftrightarrow x=\dfrac{74}{49}\left(tm\right)\)