Question

[Đặng Minh Thắng]

giải phương trình

\(\frac{x+2}{2008}+\frac{x+3}{2007}+\frac{x+4}{2006}+\frac{x+2028}{6}=0\)

Answer 1

[Trần Đình Nam]

X= -2010

Answer 2

[chelsea]

(x+2/2008+1)+(x+3/2007+1)+(x+4/2006+1)+(x+2028/6-3)=0

=x+2010/2008+ x+2010/2007+ x+2010/2006+ x+2010/6=0

=(x+2010)(1/2008+1/2007+1/2006+1/6)=

VÌ 1/2008 +1/2007 +1/2006+1/6 khác 0

=>x+2010=0=>x=-2010