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`@` `\text {Ans}`
`\downarorw`
`2^x \div 2 = 128?`
`=> 2^x = 128 * 2`
`=> 2^x = 256`
`=> 2^x = 2^8`
`=> x = 8`
Vậy, `x = 8`
______
`4^x \div 4^3 = 16`
`=> 4^x = 16 * 4^3`
`=> 4^x = 4^2 * 4^3`
`=> 4^x = 4^5`
`=> x = 5`
Vậy, ` x = 5`
________
`12^x \div 3 = 48 ?`
`=> 12^x = 48 * 3`
`=> 12^x = 144`
`=> 12^x = 12^2`
`=> x = 2`
Vậy, `x = 2`
________
`3^x - 5 = 81`
`3^x = 81 + 5`
`3^x = 86`
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`@` `\text {Kaizuu lv uuu}`
![](https://rs.olm.vn/images/avt/0.png?1311)
a) x=3
b) x=1
c) x=1 hoặc -5
d) x=2
e) x=2
g) x=2
h) x=1 hoặc x=0 hoặc x=-1
i) x=-1 hoặc x=0
\(a.4^x=64\)
\(4^x=4^3\)
\(\Rightarrow x=3\)
\(b,3^{x\times4}=81\)
\(3^{x\times4}=3^4\)
\(x\times4=4\)
\(\Rightarrow x=1\)
\(c,\left(2+x\right)^4=81\)
\(\left(2+x\right)^4=3^4\)
\(2+x=3\)
\(x=3-2\)
\(x=1\)
\(d,5^{x\times5}=125\)
\(5^{x\times5}=5^3\)
\(x\times5=3\)
\(x=3:5\)
\(x=\frac{3}{5}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 1:
a) \(33^{2x}:11^{2x}=81\)\(\Leftrightarrow\left(33:11\right)^{2x}=81\)
\(\Leftrightarrow3^{2x}=3^4\)\(\Leftrightarrow2x=4\)\(\Leftrightarrow x=2\)
Vậy \(x=2\)
b) \(\frac{x}{-5}=\frac{4}{21}\)\(\Leftrightarrow21x=-20\)\(\Leftrightarrow x=\frac{-20}{21}\)
Vậy \(x=\frac{-20}{21}\)
Bài 2:
\(A=\frac{1+3^4+3^8+3^{12}}{1+3^2+3^4+3^6+3^8+3^{10}+3^{12}+3^{14}}\)
\(=\frac{1+3^4+3^8+3^{12}}{\left(1+3^4+3^8+3^{12}\right)+\left(3^2+3^6+3^{10}+3^{14}\right)}\)
\(=\frac{1+3^4+3^8+3^{12}}{\left(1+3^4+3^8+3^{12}\right)+3^2.\left(1+3^4+3^8+3^{12}\right)}\)
\(=\frac{1+3^4+3^8+3^{12}}{\left(1+3^4+3^8+3^{12}\right).\left(1+3^2\right)}=\frac{1}{1+3^2}=\frac{1}{1+9}=\frac{1}{10}\)
\(33^{2x}:11^{2x}=81\)!
\(\left(33:11\right)^{2x}=81\)
\(3^{2x}=81\)
\(3^{2x}=3^4\)
\(2x=4\)
\(x=4:2\)
\(x=2\)
vậy \(x=2\)
\(\frac{x}{-5}=\frac{4}{21}\)
x.21=-5.4
x.21=-20
x=-20:21
\(x=-\frac{20}{21}\)
vậy \(x=-\frac{20}{21}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 15 - x = 1 - ( -9 )
15 - x = 10
x = 15 - 10
x = 5 thuộc Z
vậy____
b) -2 | x | + 15 = 1
-2 | x | = 1 - 15
-2 | x | = - 14
| x | = -14 : (-2)
| x | = 7
\(\Rightarrow x=\pm7\) thuộc Z
vậy_____
c) -3 . | x + 4 | = -18
| x + 4 | = -18 : (-3)
| x + 4 | = 6
\(\Rightarrow\orbr{\begin{cases}x+4=6\\x+4=-6\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=2\in Z\\x=-10\in Z\end{cases}}\)
Vậy_____
d) ( x - 3 ) . ( x2 + 1 ) = 0
\(\Rightarrow\orbr{\begin{cases}x-3=0\\x^2+1=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=3\in Z\\x\in\varnothing\end{cases}}\)
vậy x = 3
e) 12 - ( 9 - 3x) = - 2 . ( x + 5 )
=> 12 - 9 + 3x = -2x + (-2).5
=> 3 + 3x = -2x + (-10)
=> 3x + 2x = (-10) - 3
=> 5x = -13
=> x = -13 : 5
=> x = \(\frac{-13}{5}\notin Z\)
=> \(x\in\varnothing\)
f) ( x - 2 )3 = - 125
\(\Rightarrow\left(x-2\right)^3=\left(-5\right)^3\)
\(\Rightarrow x-2=5\)
\(\Rightarrow x=7\in Z\)
vậy____
g) ( x + 6 ) = 81
=> x = 81 - 6
=> x = 75 thuộc Z
vậy_____
h) -12 : | x - 4 | = - 4
=> |x-4| = -12 : (-4)
=> |x-4| = 3
\(\Rightarrow\orbr{\begin{cases}x-4=3\\x-4=-3\end{cases}}\Rightarrow\orbr{\begin{cases}x=7\in Z\\x=1\in Z\end{cases}}\)
vậy_____
a) 15 - x = 1 - ( -9 )
15 - x = 10
x = 15 - 10
x = 5
b) -2 | x | + 15 = 1
-2 x = 1 -15
- 2 x = -14
x = -14 : ( -2 )
x = 7
c) -3 . | x + 4| = -18
| x + 4 | = ( - 18 ) : ( - 3 )
| x + 4 | = 6
=> \(\orbr{\begin{cases}x+4=6\\x+4=-6\end{cases}\Rightarrow\orbr{\begin{cases}x=6-4\\x=-6-4\end{cases}\Rightarrow}\orbr{\begin{cases}x=2\\x=-8\end{cases}}}\)
Vậy x = 2 hoặc -8
d) ( x - 3 ) . ( x2 + 1 ) = 0
=> \(\orbr{\begin{cases}x-3=0\\x^2+1=0\end{cases}\Rightarrow\orbr{\begin{cases}x=0+3\\x^2=0-1\end{cases}\Rightarrow}\orbr{\begin{cases}x=3\\x^2=-1\end{cases}\Rightarrow}\orbr{\begin{cases}x=3\\x=-1\end{cases}}}\)
Vậy x = 3 hoặc -1
![](https://rs.olm.vn/images/avt/0.png?1311)
a, 410. 230=220.230=250
b,925.274.813= 350.312.312=374
Tương tự các câu khác....
a, 410.230 = (22)10.230 = 220.230 = 250
b, 925.274.813 = (32)25.(33)4.(34)3 = 350.312.312 = 374
c, 2550.1255 = (52)50.(53)5 = 5100.515 = 5115
d, 643.48.164 = (26)3.(22)8.(24)4 = 218.216.216 = 250
e, 38 : 36 = 32
210 : 83 = 210 : (23)3 = 210 : 29 = 2
127 : 67 = (12 : 6)7 = 27
@Dương Tuyết Mai
\(\left(x+\dfrac{4}{3}\right)^4=\dfrac{1}{81}\\ =>\left(x+\dfrac{4}{3}\right)^4=\left(\dfrac{1}{3}\right)^4\)
TH1: `x+4/3=1/3`
`=>x=1/3-4/3`
`=>x=-3/3`
`=>x=-1`
TH2: `x+4/3=-1/3`
`=>x=-1/3-4/3`
`=>x=-5/3`
Vậy: ...