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a) \(-x-14+32=-26\)
\(-x=-26-32+14\)
\(-x=-44\)
\(x=44\)
b) \(-152-\left(3x+1\right)=\left(-2\right)\left(-27\right)\)
\(-152-3x-1=54\)
\(-3x=96\)
\(x=-32\)
c) \(x+x+x+82=-2-x\)
\(3x+82=2+x\)
\(2x=-80\)
\(x=-40\)
d) \(\left(-1\right)\left(-3\right)\left(-6\right)x=36\)
\(-18x=36\)
\(x=-2\)
1)
\(-x-14+32=-26\)
\(\Rightarrow-x+18=-26\)
\(\Rightarrow-x=-26-18\)
\(\Rightarrow-x=-44\)
\(\Rightarrow x=44\)
Vậy \(x=44\)
2)
\(-152-\left(3x+1\right)=\left(-2\right)\left(-27\right)\)
\(\Rightarrow-152-3x-1=54\)
\(\Rightarrow-153-3x=54\)
\(\Rightarrow-3x=54+163\)
\(\Rightarrow-3x=207\)
\(\Rightarrow x=207:\left(-3\right)\)
\(\Rightarrow x=-69\)
Vậy \(x=-69\)
3)
\(x+x+x+82=-2-x\)
\(\Rightarrow3x+82=-2-x\)
\(\Rightarrow3x+x=-2-82\)
\(\Rightarrow4x=-84\)
\(\Rightarrow x=-21\)
Vậy \(x=-21\)
4)
\(\left(-1\right)\left(-3\right)\left(-6\right).x=36\)
\(\Rightarrow-18x=36\)
\(\Rightarrow x=-2\)
Vậy \(x=-2\)
Ta có: \(\frac{2n}{64}=26\)
\(\frac{n}{32}=26\)
\(n=26.32\)
\(n=832\)
\(2^n-64=26\Rightarrow2^n=90\Rightarrow n=log_290\notinℕ\)Đề lag r
a)(-6-18):(-4)
= { (-6) + (-8) } : (-4)
=(-24) : (-4)= (-6)
b)-28.(50-42)-35.(34-62)
= -28.8-35.(-28)
= -28.(8-35)
= -28.(-27)=756
c)-18-(-5)+26
= -18+5+26
= -13+26=13
d)-72.69+31.(-72)
= -72.(69+31)
= -72.100=-7200
`Answer:`
a. \(\frac{17}{2}-\left|2x-\frac{3}{4}\right|=-\frac{7}{4}\)
\(\Leftrightarrow\left|2x-\frac{3}{4}\right|=\frac{17}{2}+\frac{7}{4}\)
\(\Leftrightarrow\left|2x-\frac{3}{4}\right|=\frac{41}{4}\)
\(\Leftrightarrow\orbr{\begin{cases}2x-\frac{3}{4}=\frac{41}{4}\\2x-\frac{3}{4}=-\frac{41}{4}\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}2x=\frac{41}{4}+\frac{3}{4}\\2x=-\frac{41}{4}+\frac{3}{4}\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}2x=11\\2x=-\frac{19}{2}\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=11:2\\x=-\frac{19}{2}:2\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=\frac{11}{2}\\x=-\frac{19}{4}\end{cases}}\)
b. \(\left(x+\frac{1}{5}\right)^2+\frac{17}{25}=\frac{26}{25}\)
\(\Leftrightarrow\left(x+\frac{1}{5}\right)^2=\frac{26}{25}-\frac{17}{25}\)
\(\Leftrightarrow\left(x+\frac{1}{5}\right)^2=\frac{9}{25}\)
\(\Leftrightarrow\left(x+\frac{1}{5}\right)=\left(\frac{3}{5}\right)^2\)
\(\Leftrightarrow\orbr{\begin{cases}x+\frac{1}{5}=\frac{3}{5}\\x+\frac{1}{5}=-\frac{3}{5}\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=\frac{3}{5}-\frac{1}{5}\\x=-\frac{3}{5}-\frac{1}{5}\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=\frac{2}{5}\\x=-\frac{4}{5}\end{cases}}\)
c. \(-1\frac{5}{27}-\left(3x-\frac{7}{9}\right)^3=-\frac{24}{27}\)
\(\Leftrightarrow-\frac{32}{27}-\left(3x-\frac{7}{9}\right)^3=-\frac{24}{27}\)
\(\Leftrightarrow\left(3x-\frac{7}{9}\right)^3=-\frac{32}{27}-\left(-\frac{24}{27}\right)\)
\(\Leftrightarrow\left(3x-\frac{7}{9}\right)^3=-\frac{8}{27}\)
\(\Leftrightarrow\left(3x-\frac{7}{9}\right)^3=\left(-\frac{2}{3}\right)^3\)
\(\Leftrightarrow3x-\frac{7}{9}=-\frac{2}{3}\)
\(\Leftrightarrow3x=-\frac{2}{3}+\frac{7}{9}\)
\(\Leftrightarrow3x=\frac{1}{9}\)
\(\Leftrightarrow x=\frac{1}{9}:3\)
\(\Leftrightarrow x=\frac{1}{27}\)
tìm STN x sao cho x nhỏ hơn hoặc bằng 200 . bt rằng khi chia x cho STN y thì đc thương là 4 và dư 35
Bài 1:
x/-3=9/4
nên x=-9/4*3=-27/4
2x+y=-4
=>y=-4-2x=-4-2*(-27/4)=-4+27/2=27/2-8/2=19/2
$9 . 2^{3x-1} = 36$
$\Rightarrow 2^{3x-1} = 36 : 9$
$\Rightarrow 2^{3x-1} = 4$
$\Rightarrow 2^{3x-1} = 2^{2}$
$\Rightarrow 3x - 1 = 2$
$ 3x = 2 + 1$
$ 3x = 3$
$ x = 3 : 3$
$ x = 1$
Vậy `x = 1`
\(3^{x-4}-17=2^6\)
\(\Rightarrow3^{x-4}-17=64\)
\(\Rightarrow3^{x-4}=64+17\)
\(\Rightarrow3^{x-4}=81\)
\(\Rightarrow3^{x-4}=3^4\)
$\Rightarrow x - 4 = 4$
$ x = 4 + 4$
$ x = 8$
Vậy `x = 8`
x = 1
x = 8