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Bài 1
a) \(\dfrac{3}{8}+\dfrac{5}{8}=\dfrac{8}{8}=1\)
b) \(\dfrac{3}{4}+\dfrac{-7}{16}=\dfrac{12}{16}+\dfrac{-7}{16}=\dfrac{5}{16}\)
c) \(2\dfrac{17}{20}-\dfrac{1}{2}+3\dfrac{3}{20}=\dfrac{57}{20}-\dfrac{1}{2}+\dfrac{63}{20}\)\(=\dfrac{47}{20}+\dfrac{63}{20}=\dfrac{110}{20}=\dfrac{11}{2}\)
d) \(\dfrac{2}{3}-2\dfrac{1}{8}+\dfrac{7}{24}=\dfrac{2}{3}-\dfrac{17}{8}+\dfrac{7}{24}=\dfrac{16}{24}-\dfrac{51}{24}+\dfrac{7}{24}=\dfrac{16-51+7}{24}=\dfrac{-28}{24}=\dfrac{-7}{6}\)
Bài 2 :
a) \(x-\dfrac{7}{4}=3\)
\(x=3+\dfrac{7}{4}\)
\(x=\dfrac{19}{4}\)
b) \(x-\dfrac{1}{2}=\dfrac{4}{16}\cdot\dfrac{8}{3}\)
\(x-\dfrac{1}{2}=\dfrac{2}{3}\)
\(x=\dfrac{2}{3}+\dfrac{1}{2}\)
\(x=\dfrac{5}{6}\)
c) \(\dfrac{15}{11}\div x=\dfrac{45}{22}\)
\(x=\dfrac{15}{11}\div\dfrac{45}{22}\)
\(x=\dfrac{2}{3}\)
d) \(\dfrac{8}{3}-2x=\dfrac{8}{5}-1\)
\(\dfrac{8}{3}-2x=\dfrac{3}{5}\)
\(2x=\dfrac{8}{3}-\dfrac{3}{5}\)
\(2x=\dfrac{31}{15}\)
\(x=\dfrac{31}{15}\div2\)
\(x=\dfrac{31}{30}\)
a: MN=7+5=12cm
b: MK=12/2=6cm
OK=6-5=1cm
c: Vì OK<ON
nên K thuộc tia ON
a: MN=7+5=12cm
b: MK=12/2=6cm
OK=6-5=1cm
c: Vì OK<ON
nên K thuộc tia ON
\(\left(0,75-\frac{1}{4}\right):\frac{5}{6}=\left(\frac{3}{4}-\frac{1}{4}\right):\frac{5}{6}\)
\(=\frac{1}{2}:\frac{5}{6}=\frac{3}{5}\)
C1:(0,75-1/4):5/6
=(3/4-1/4):5/6
=1/2:5/6
=3/5
C2:(0,75-1/4):5/6
=(0,75-0,25). 6/5
=0,5.1,2
= 0.6
|-x - 5 | + 2 = 3
<=> | -x - 5| = 1
\(\Leftrightarrow\orbr{\begin{cases}-x-5=1\\-x-5=-1\end{cases}\Leftrightarrow\orbr{\begin{cases}x=-6\\-4\end{cases}}}\)
\(\dfrac{2^6.18+2^7}{2^6.5^2-2^6.3}=\dfrac{2^6\left(18+2\right)}{2^6.\left(5^2-3\right)}=\dfrac{20}{5^2-3}=\dfrac{20}{25-3}=\dfrac{20}{22}=\dfrac{10}{11}\)
\(=\dfrac{2^6.18+2^6.2}{2^6.25-2^6.3}=\dfrac{2^6\left(18+2\right)}{2^6\left(25-3\right)}=\dfrac{18+2}{25-3}=\dfrac{20}{22}=\dfrac{10}{11}\)
\(\dfrac{4}{3}\cdot\dfrac{9}{8}\cdot\dfrac{16}{15}\cdot...\cdot\dfrac{400}{399}\)
\(=\dfrac{2\cdot2}{1\cdot3}\cdot\dfrac{3\cdot3}{2\cdot4}\cdot\dfrac{4\cdot4}{3\cdot5}\cdot...\cdot\dfrac{20\cdot20}{19\cdot21}\)
\(=\dfrac{2\cdot2\cdot3\cdot3\cdot4\cdot4\cdot...\cdot20\cdot20}{1\cdot3\cdot2\cdot4\cdot3\cdot5\cdot...\cdot19\cdot21}\)
\(=\dfrac{2\cdot3\cdot4\cdot...\cdot20}{1\cdot2\cdot3\cdot...\cdot19}\cdot\dfrac{2\cdot3\cdot4\cdot...\cdot20}{3\cdot4\cdot5\cdot...\cdot21}\)
\(=20\cdot\dfrac{2}{21}\)
\(=\dfrac{40}{21}\)
c,số đó là
-10/27:5/9=-2/3
d,số đó là
90:30%=300
a) Số đó là
\(\dfrac{-10}{27}:\dfrac{5}{9}=\dfrac{-2}{3}\)
b) Số đó là
\(90:30\%=300\)