Câu hỏi của Lê Khôi Nguyên

Question

làm cho mình bài 2 câu 2 từ phần a đến phần g thoi

HT.Phong (9A5) · Accepted Answer

Bài 2:$a,2^{10}+2^9\
=2^9\cdot\left(2+1\right)\
=3\cdot2^9⋮3\
b,2^{10}+2^9+2^8\
=2^8\cdot\left(2^2+2+1\right)\
=7\cdot2^8⋮7\
c,5^{2023}+5^{2022}\
=5^{2022}\cdot\left(5+1\right)\
=6\cdot5^{2022}⋮6\
d,2^{10}-3\cdot2^7\
=2^7\cdot\left(2^3-3\right)\
=5\cdot2^7⋮5\
e,7^{10}-7^8\
=7^8\cdot\left(7^2-1\right)\
=7^8\cdot48⋮48\
f,16^5+2^{15}\
=\left(2^4\right)^5+2^{15}\
=2^{20}+2^{15}\
=2^{15}\cdot\left(2^5+1\right)\
=33\cdot2^{15}⋮33\
g,8^8+4^{10}\
=\left(2^3\right)^8+\left(2^2\right)^{10}\
=2^{24}+2^{20}\
=2^{20}\cdot\left(2^4+1\right)\
=17\cdot2^{20}⋮17\
h,81^7-27^9-9^{13}\
=\left(3^4\right)^7-\left(3^3\right)^9-\left(3^2\right)^{13}\
=3^{28}-3^{27}-3^{26}\
=3^{26}\cdot\left(3^2-3-1\right)\
=3^{26}\cdot5\
=3^{24}\cdot\left(3^2\cdot5\right)\
=45\cdot3^{24}⋮45$Câu trả lời: Bài 2:$a,2^{10}+2^9\
=2^9\cdot\left(2+1\right)\
=3\cdot2^9⋮3\
b,2^{10}+2^9+2^8\
=2^8\cdot\left(2^2+2+1\right)\
=7\cdot2^8⋮7\
c,5^{2023}+5^{2022}\
=5^{2022}\cdot\left(5+1\right)\
=6\cdot5^{2022}⋮6\
d,2^{10}-3\cdot2^7\
=2^7\cdot\left(2^3-3\right)\
=5\cdot2^7⋮5\
e,7^{10}-7^8\
=7^8\cdot\left(7^2-1\right)\
=7^8\cdot48⋮48\
f,16^5+2^{15}\
=\left(2^4\right)^5+2^{15}\
=2^{20}+2^{15}\
=2^{15}\cdot\left(2^5+1\right)\
=33\cdot2^{15}⋮33\
g,8^8+4^{10}\
=\left(2^3\right)^8+\left(2^2\right)^{10}\
=2^{24}+2^{20}\
=2^{20}\cdot\left(2^4+1\right)\
=17\cdot2^{20}⋮17\
h,81^7-27^9-9^{13}\
=\left(3^4\right)^7-\left(3^3\right)^9-\left(3^2\right)^{13}\
=3^{28}-3^{27}-3^{26}\
=3^{26}\cdot\left(3^2-3-1\right)\
=3^{26}\cdot5\
=3^{24}\cdot\left(3^2\cdot5\right)\
=45\cdot3^{24}⋮45$

2x+1	-55	-11	-5	-1	1	5	11	55
3y-2	1	5	11	55	-55	-11	-5	-1
2x	-56	-12	-6	-2	0	4	10	54
3y	3	7	13	57	-53	-9	-3	1
x	-28	-6	-3	-1	0	2	5	27
y	1			19		-3	-1

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