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5 tháng 8 2022
2: =>2x-1/4=5/6-1/2x
=>5/2x=5/6+1/4=13/12
=>x=13/30
3: =>3x-5/6=2/3-1/2x
=>3,5x=2/3+5/6=4/6+5/6=9/6=3,2
hay x=32/35
S
28 tháng 6 2019
\(a,\frac{3x+2}{5x+7}=\frac{3x-1}{5x-1}=\frac{\left(3x+2\right)-\left(3x-1\right)}{\left(5x+7\right)-\left(5x-1\right)}=\frac{3}{8};\frac{3x+2}{5x+7}=\frac{3}{8}\Leftrightarrow24x+16=15x+21\Leftrightarrow9x=5\Leftrightarrow x=\frac{5}{9}\) \(b,\frac{37-x}{x+13}=\frac{3}{7}\Leftrightarrow37.7-7x=3x+39\Leftrightarrow259-7x=3x+39\Leftrightarrow220-7x=3x\Leftrightarrow10x=220\Leftrightarrow x=22\) \(c,\frac{x+1}{2x+1}=\frac{0,5x+2}{x+3}=\frac{x+4}{2x+6}=\frac{\left(x+4\right)-\left(x+1\right)}{2x+6-\left(2x+1\right)}=\frac{3}{5};\frac{x+1}{2x+1}=\frac{3}{5}\Leftrightarrow5x+5=6x+3\Leftrightarrow x=2\) \(d,\frac{x-2}{x+2}=\frac{x+3}{x-4}=\frac{\left(x+3\right)-\left(x-2\right)}{\left(x-4\right)-\left(x+2\right)}=\frac{5}{-6};\frac{x-2}{x+2}=\frac{5}{-6}\Leftrightarrow6\left(2-x\right)=5x+10\Leftrightarrow2-6x=5x\Leftrightarrow x=\frac{2}{11}\) \(f,\frac{3x-5}{x}=\frac{9x}{3x+2}=\frac{9x-15}{3x}=\frac{9x-\left(9x-15\right)}{\left(3x+2\right)-3x}=\frac{15}{2};\frac{9x}{3x+2}=\frac{15}{2}\Leftrightarrow18x=45x+30\Leftrightarrow27x+30=0\Leftrightarrow x=\frac{-10}{9}\) \(e,\frac{x+2}{6}=\frac{5x-1}{5}\Leftrightarrow5\left(x+2\right)=6\left(5x-1\right)\Leftrightarrow5x+10=30x-6\Leftrightarrow10=25x-6\Leftrightarrow25x=16\Leftrightarrow x=\frac{16}{25}\)
MA
24 tháng 8 2016
\(\frac{2}{3}x+\frac{5}{7}=\frac{3}{10}\)
\(\Rightarrow\frac{2}{3}x=\frac{3}{10}-\frac{5}{7}\)
\(\Rightarrow\frac{2}{3}x=-\frac{29}{70}\)
\(\Rightarrow x=-\frac{29}{70}:\frac{2}{3}\)
\(\Rightarrow x=-\frac{87}{140}\)
tíc mình nha
22 tháng 12 2017
a) \(4:\left(x-1\right)=\left(x-1\right):9\)
\(\frac{4}{x-1}=\frac{x-1}{9}\)
\(\left(x-1\right)^2=36\)
\(\left(x-1\right)^2=6^2\)
\(\Rightarrow x-1=6\)
\(\Rightarrow x=7\)
vậy \(x=7\)
c) \(3\frac{1}{2}:x\frac{1}{2}=5\frac{1}{3}:\frac{1}{2}.1\frac{1}{5}\)
\(\frac{7}{2}:\frac{1}{2}x=\frac{16}{3}:\frac{1}{2}.\frac{6}{5}\)
\(\frac{7}{2}:\frac{1}{2}x=\frac{64}{5}\)
\(\frac{1}{2}x=\frac{7}{2}:\frac{64}{5}\)
\(\frac{1}{2}x=\frac{35}{128}\)
\(x=\frac{35}{128}:\frac{1}{2}\)
\(x=\frac{35}{64}\)
d) \(\left|2x-3\right|=5\)
\(\Rightarrow\orbr{\begin{cases}2x-3=5\\2x-3=-5\end{cases}}\Rightarrow\orbr{\begin{cases}2x=8\\2x=-2\end{cases}}\Rightarrow\orbr{\begin{cases}x=4\\x=-1\end{cases}}\)
vậy \(\orbr{\begin{cases}x=4\\x=-1\end{cases}}\)
f) \(\left(2x-\frac{1}{2}\right)^2=\left(1-3x\right)^2\)
\(\Rightarrow2x-\frac{1}{2}=1-3x\)
\(\Rightarrow2x+3x=1+\frac{1}{2}\)
\(\Rightarrow5x=\frac{3}{2}\)
\(\Rightarrow x=\frac{3}{10}\)
\(\left(3-\frac{1}{2}:x\right)^2=14\)
\(\left(3-\frac{1}{2x}\right)^2=14\)
\(\frac{1}{4x^2}-2.\frac{1}{2x}.3+9=14\)
\(\frac{1}{4x^2}-\frac{3}{x}=5\)
\(\left(\frac{1}{4x}-3\right):x=5\)
22 tháng 7 2019
Câu 1: ĐẶt \(\frac{x}{5}=\frac{y}{4}=k\)\(\Rightarrow x=5k;......y=4k\)
Ta có: \(x^2y=\left(5k\right)^2.\left(4k\right)=400k^3=100\)
\(\Rightarrow k^3=\frac{1}{4}\Rightarrow k=\sqrt[3]{\frac{1}{4}}\)
Vậy \(x=5k=4\sqrt[3]{\frac{1}{4}}\)
\(y=4.\sqrt[3]{\frac{1}{4}}\)
Câu 3 4 5 tương tư:
câu 2. bạn biến đổi: \(5x=2y\Leftrightarrow\frac{x}{2}=\frac{y}{5}\)thì sẽ trở thành dạng quen thuộc ở trên. :))
\(\frac{x+2}{5}=\frac{2-3x}{3}\)
\(\Leftrightarrow3\left(x+2\right)=5\left(2-3x\right)\)
\(\Leftrightarrow3x+6=10-15x\)
\(\Leftrightarrow3x+15x=10-6\)
\(\Leftrightarrow18x=4\)
\(\Leftrightarrow x=\frac{2}{9}\)
\(\frac{x+2}{5}=\frac{2-3x}{3}\)
\(\Leftrightarrow3\left(x+2\right)=5\left(2-3x\right)\)
\(\Leftrightarrow3x+6=10-15x\)
\(\Leftrightarrow3x+15x=10-6\)
\(\Leftrightarrow18x=4\)
\(\Leftrightarrow x=\frac{4}{18}=\frac{2}{9}\)