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x/4=6/8 3x+1/3=5/2 x-3-1/7=0
x.8=4.6=24 3x=5/2-1/3=13/6 x-3=0+1/7=1/7
x=24:8=3 x=13/6:3=13/18 x=1/7+3=22/7
\(\frac{x}{4}=\frac{6}{8}\Rightarrow x\times8=4.6\Rightarrow x=\frac{4.6}{8}3\)
Vậy x=3
3x\(+\frac{1}{3}=\frac{5}{2}\)
3x =\(\frac{5}{2}-\frac{1}{3}\)
3x =\(\frac{13}{6}\)
x =\(\frac{13}{6}:3=\frac{13}{6}.\frac{1}{3}\)
x =\(\frac{13}{18}\)
x-3-\(\frac{1}{7}=0\)
x-3 =0+\(\frac{1}{7}\)
x-3 =\(\frac{1}{7}\)
x =\(\frac{1}{7}+3\)
x =3\(\frac{1}{7}\)
\(\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{x.\left(x+1\right)}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{x}-\frac{1}{x+1}\)
\(=1-\frac{1}{x+1}=\frac{x+1}{x+1}-\frac{1}{x+1}=\frac{x}{x+1}\)
\(\frac{x}{9}< \frac{4}{7}< \frac{x+1}{9}\)
\(\Rightarrow\frac{7x}{63}< \frac{36}{63}< \frac{7x+7}{63}\)
\(\Rightarrow7x< 36< 7x+7\)
\(\Rightarrow x< \frac{36}{7}< x+1\)
\(\Rightarrow x< 5\frac{1}{7}< x+1\)
\(\Rightarrow x=5\)
\(\frac{x+2}{x-1}=\frac{x-3}{x+1}\Leftrightarrow\left(x+2\right)\left(x+1\right)=\left(x-1\right)\left(x-3\right)\Leftrightarrow x^2+3x+2=x^2-4x+3\)
\(\Leftrightarrow x^2+3x+2-x^2+4x-3=0\Leftrightarrow7x-1=0\Leftrightarrow7x=1\Leftrightarrow x=\frac{1}{7}\)
=>(x+2)(x+1)=(x-1)(x-3)
x.x+x.1+2x+2.1=x.x-3x-1x+1.3
x2+x+2x+2=x2-3x-1x+3
x2+(x+2x)+2=x2+(-3x-1x)+3
x2+3x+2=x2-4x+3
x2+3x-x2+4x=3-2
(x2-x2)+(3x+4x)=1
7x=1
x=1/7
Đề phải cho x < = y chứ bạn ơi
Xét: x.(y+2018)-y.(x+2018)
= xy+2018x-xy-2018y
= 2018,(x-y) < = 0
=> x.(y+2018) < = y.(x+2018)
=> x/y < = x+2018/y+2018
=> ĐPCM
k mk nha