Question

[Nguyễn Ngọc Thái Thanh]

\(\frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4}\); x-2y+3z=14

tim x y z

Answer 1

[hong pham]

\(\frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4}\) \(\Rightarrow\frac{x-1}{2}=\frac{2y-4}{6}=\frac{3z-9}{12}\)

Áp dụng tính chất dãy tỉ số bằng nhau ta có:

\(\frac{x-1}{2}=\frac{2y-4}{6}=\frac{3z-9}{12}=\frac{x-1-2y-4+3z-9}{2-6+12}=\frac{\left(x-2y+3z\right)-\left(1+4+9\right)}{8}=\frac{14-14}{8}=0\)

\(x=0.2+1=1\) ; \(y=\left(0.6+4\right):2=2\) ; \(z=\left(0.12+9\right):3=3\)