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a, 6/9+5/7+1/3=2/3+5/7+1/3=5/7+1=12/7
b, 17/7+6/5-20/14=17/7+6/5-10/7=6/5+1=11/5
c,2/5x1/4+3/4x2/5=2/5x(1/4+3/4)=2/5x1=2/5
d, 6/11:4/6+5/11:2/3=6/11:2/3+5/11:2/3=(6/11+5/11):2/3=3/2
nha
\(\frac{a}{b}\cdot4+\frac{1}{6}=\frac{17}{6}\)
\(\frac{a}{b}\cdot4=\frac{17}{6}-\frac{1}{6}\)
\(\frac{a}{b}\cdot4=\frac{8}{3}\)
\(\frac{a}{b}=\frac{1}{6}\)
\(\frac{a}{b}\cdot4+\frac{1}{6}=\frac{17}{6}\)
\(4\cdot\frac{a}{b}=\frac{8}{3}\)
\(\frac{a}{b}=\frac{2}{3}\)
\(\frac{a}{b}\times4+\frac{1}{6}=\frac{17}{6}\)
\(\frac{a}{b}\times4=\frac{17}{6}-\frac{1}{6}\)
\(\frac{a}{b}\times4=\frac{8}{3}\)
\(\frac{a}{b}=\frac{8}{3}\div4\)
\(\frac{a}{b}=\frac{2}{3}\)
K mk nha
Mk cảm ơn bạn nhiều
Thank you so much!
\(\frac{1}{6}.\frac{1}{3}+\frac{17}{6}.\frac{1}{3}+\frac{2015}{2016}-1\)
\(=\frac{1}{3}\left(\frac{1}{6}+\frac{17}{6}\right)+\frac{2015}{2016}-1\)
\(=\frac{1}{3}.3+\frac{2015}{2016}-1\)
\(=1-1+\frac{2015}{2016}=\frac{2015}{2016}\)
\(\frac{1}{6}\times\frac{1}{3}+\frac{17}{6}\times\frac{1}{3}+\frac{2015}{2016}-1\)
\(=\left(\frac{1}{6}+\frac{17}{6}\right)\times\frac{1}{3}+\frac{2015}{2016}-1\)
\(=3\times\frac{1}{3}+\frac{2015}{2016}-1\)
\(=1+\frac{2015}{2016}-1\)
\(=0+\frac{2015}{2016}=\frac{2015}{2016}\)
a) 1200 : 24 - ( 17 - x ) = 36
50 - ( 17 - x ) = 36
17 - x = 50 - 36 = 14
x = 17 - 14 = 3
b) 4/x = 4/21. Ở trường hợp này thì ta làm như sau.
x = 4 : 4/21 = 21
4/ x = 2/7. Ở trường hợp này ta làm như sau.
x = 4 : 2/7 = 14
c) x : 6/7 + 2/3 = 7/3
x : 6/7 = 7/3 - 2/3
x : 6/7 = 5/3
x = 5/3 x 6/7 = 10/7
Đáp số: a) 3 ; b) 21 và 14 ; c) 10/7
a) 1200 : 24 - ( 17 - x ) = 36
50 - ( 17 - x) = 36
17-x =50-36
17-x = 14
x =17-14
x =3
b)\(\frac{4}{x}=\frac{4}{21}=\frac{2}{7}\)
\(=\frac{4}{3}=\frac{4}{21}=\frac{2}{7}\)
c) x : \(\frac{6}{7}+\frac{2}{3}=\frac{7}{3}\)
x : \(\frac{32}{21}\) \(=\frac{7}{3}\)
x = \(\frac{7}{3}\times\frac{32}{21}\)
x = \(\frac{32}{9}\)
Bn tk mk nếu mk đúng nhé và mk ns lun bài này là mk tự nghĩ hết nhen
\(\frac{23}{12}\)
\(\frac{314}{105}\)
\(\frac{59}{60}\)
\(\frac{199}{90}\)
\(\frac{1}{18}\)
\(\frac{13}{36}\)
\(\frac{4}{221}\)
\(\frac{4}{85}\)
\(\left(a\right)\frac{34-x}{30}=\frac{5}{6}\)
\(\frac{34-x}{30}=\frac{25}{30}\)
34 - x = 25
x = 34 - 25 = 9
\(\left(b\right)\frac{x+13}{34}=\frac{12}{17}\)
\(\frac{x+13}{34}=\frac{24}{34}\)
x + 13 = 24
x = 24 - 13 = 11
\(\left(c\right)\left(x+\frac{1}{3}\right)+\left(x+\frac{1}{9}\right)+\left(x+\frac{1}{27}\right)+\left(x+\frac{1}{81}\right)=\frac{56}{81}\)
\(4x+\frac{1}{3}+\frac{1}{9}+\frac{1}{27}+\frac{1}{81}=\frac{56}{81}\)
Đặt \(A=\frac{1}{3}+\frac{1}{9}+\frac{1}{27}+\frac{1}{81}\)
Ta có : \(3A=1+\frac{1}{3}+\frac{1}{9}+\frac{1}{27}\)
\(3A-A=1+\frac{1}{3}+\frac{1}{9}+\frac{1}{27}-\frac{1}{3}-\frac{1}{9}-\frac{1}{27}-\frac{1}{81}\)
\(2A=1-\frac{1}{81}=\frac{80}{81}\)
\(A=\frac{80}{81}\div2=\frac{40}{81}\)
\(\Rightarrow4x+\frac{40}{81}=\frac{56}{81}\)
\(4x=\frac{56}{81}-\frac{40}{81}\)
\(4x=\frac{16}{81}\)
\(x=\frac{16}{81}\div4=\frac{4}{81}\)
\(\frac{a}{b}x4\frac{1}{6}=\frac{17}{6}\)
\(\frac{a}{b}x\frac{25}{6}=\frac{17}{6}\)
\(\frac{a}{b}=\frac{17}{6}:\frac{25}{6}\)
\(\frac{a}{b}=\frac{17}{25}\)
sai bét
\(\frac{a}{b}x4+\frac{1}{6}=\frac{17}{6}\)
\(\Rightarrow\frac{a}{b}x4=\frac{17}{6}-\frac{1}{6}\)
\(\Rightarrow\frac{a}{b}x4=\frac{8}{3}\)
\(\Rightarrow\frac{a}{b}=\frac{8}{3}:4\)
\(\Rightarrow\frac{a}{b}=\frac{2}{3}\)