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Tìm x trong các tỉ lệ thức sau :
\(\left(a\right)3,8\div\left(2x\right)=\frac{1}{4}\div2\frac{2}{3}\)
\(3,8\div\left(2x\right)=\frac{3}{32}\)
\(2x=3,8\div\frac{3}{32}\)
\(2x=40\frac{8}{15}\)
\(x=20\frac{4}{15}\)
\(\left(0,25x\right)\div3=\frac{5}{6}\div0,125\)
\(\left(0,25x\right)\div3=6\frac{2}{3}\)
\(\left(0,25x\right)=6\frac{2}{5}\times3\)
\(\left(0,25x\right)=20\)
\(x=80\)
\(0,01\div2,5=\left(0,75x\right)\div0,75\)
\(0,004=\left(0,75x\right)\div0,75\)
\(0,75x=0,75\times0,004\)
\(0,75x=0,003\)
\(x=0,004\)
\(1\frac{1}{3}\div0,8=\frac{2}{3}\div\left(0,1x\right)\)
\(1\frac{2}{3}=\frac{2}{3}\div\left(0,1x\right)\)
\(\left(0,1x\right)=\frac{2}{3}\div1\frac{2}{3}\)
\(\left(0,1x\right)=\frac{2}{5}\)
\(x=4\)
Dung ko z
c) \(x:\left(-2,14\right)=\left(-3,12\right):1,2\)
=> \(x:\left(-2,14\right)=-2,6\)
=> \(x=\left(-2,6\right).\left(-2,14\right)\)
=> \(x=5,564\)
Vậy \(x=5,564.\)
d) \(2\frac{2}{3}:x=2\frac{1}{2}:\left(-0,06\right)\)
=> \(\frac{8}{3}:x=\frac{25}{12}:\left(-\frac{3}{50}\right)\)
=> \(\frac{8}{3}:x=-\frac{625}{18}\)
=> \(x=\frac{8}{3}:\left(-\frac{625}{18}\right)\)
=> \(x=-\frac{48}{625}\)
Vậy \(x=-\frac{48}{625}.\)
Chúc bạn học tốt!
a ) \(\frac{-3}{7}+x=\frac{1}{3}\Rightarrow x=\frac{1}{3}-\frac{-3}{7}\Rightarrow x=\frac{16}{21}\)
b) \(\frac{3}{4}+\frac{1}{4}:x=\frac{2}{5}\Rightarrow\frac{1}{4}:x=\frac{2}{5}-\frac{3}{4}\Rightarrow\frac{1}{4}:x=-\frac{7}{20}\Rightarrow x=\frac{1}{4}:\left(-\frac{7}{20}\right)=-\frac{5}{7}\)
c) \(1\frac{1}{3}:0,8=\frac{2}{3}:0,1x\Rightarrow\frac{2}{3}:0,1x=\frac{5}{3}\Rightarrow0,1x=\frac{2}{5}\Rightarrow x=4\)
d) \(\left|x-3\right|=\frac{1}{2}\Rightarrow\orbr{\begin{cases}x-3=\frac{1}{2}\\x-3=-\frac{1}{2}\end{cases}\Rightarrow\orbr{\begin{cases}x=\frac{7}{2}\\x=\frac{5}{2}\end{cases}}}\)
e) \(1\frac{1}{2}.x-4=0,5\Rightarrow\frac{3}{2}x=4,5\Rightarrow x=3\)
g) \(2^{x-1}=16\Rightarrow2^{x-1}=2^4\Rightarrow x-1=4\Rightarrow x=5\)
h) \(\left(x-1\right)^2=25\Rightarrow\orbr{\begin{cases}x-1=5\\x-1=-5\end{cases}\Rightarrow\orbr{\begin{cases}x=6\\x=-4\end{cases}}}\)
i) \(\left|2x-1\right|=5\Rightarrow\orbr{\begin{cases}2x-1=5\\2x-1=-5\end{cases}\Rightarrow\orbr{\begin{cases}x=3\\x=-2\end{cases}}}\)
k) \(0,2-\left|4,2-2x\right|=0\Rightarrow\left|4,2-2x\right|=0,2\Rightarrow\orbr{\begin{cases}4,2-2x=0,2\\4,2-2x=-0,2\end{cases}\Rightarrow\orbr{\begin{cases}x=2\\x=2,2\end{cases}}}\)
a) Lm r nkoa!
b) \(\left(0,25x\right):3=\frac{5}{6}:0,125\)
\(=\left(0,25x\right):3=\frac{20}{3}\)
\(\Rightarrow0,25x=\frac{20}{3}\cdot3=20\)
\(\Rightarrow x=20:0,25=80\)
\(\Rightarrow x=80\)
c) \(0,01:2,5=\left(0,75x\right):0,75\)
\(=\frac{1}{250}=\left(0,75x\right):0,75\)
\(\Rightarrow0,75x=\frac{1}{250}\cdot0,75=\frac{3}{1000}\)
\(\Rightarrow x=\frac{3}{1000}:0,75=\frac{1}{250}\)
\(\Rightarrow x=\frac{1}{250}\)
d) \(1\frac{1}{3}:0,8=\frac{2}{3}:\left(0,1x\right)\)
\(=\frac{5}{3}=\frac{2}{3}:\left(0,1x\right)\)
\(\Rightarrow0,1x=\frac{2}{3}:\frac{5}{3}=\frac{2}{5}\)
\(\Rightarrow x=\frac{2}{5}:0,1=4\)
\(\Rightarrow4\)
Bài 1:
a) \(\frac{x}{-15}=\frac{-60}{x}\Rightarrow x^2=\left(-60\right).\left(-15\right)=900\Rightarrow x=\orbr{\begin{cases}30\\-30\end{cases}}\)
Bài 2: Đặt \(\frac{x}{4}=\frac{y}{7}=k\Rightarrow x=4k;y=7k\)
\(\Rightarrow xy=4k.7k=28k^2=112\)
\(\Rightarrow k^2=4\Rightarrow k=\pm2\)
\(\Rightarrow\orbr{\begin{cases}x=4.2=8\\x=-4.2=-8\end{cases}}\)
Và \(\orbr{\begin{cases}y=7.2=14\\y=-7.2=-14\end{cases}}\)
Bài 3: \(1\frac{1}{3}:0,8=\frac{2}{3}:\left(0,1x\right)\)
\(\Rightarrow\frac{4}{3}:\frac{4}{5}=\frac{2}{3}:\frac{1}{10}x\Rightarrow\frac{5}{3}=\frac{2}{3}:\frac{1}{10}x\)
\(\Rightarrow\frac{1}{10}x=\frac{2}{5}\Rightarrow x=4\)
Mk trả lời nốt bài 4 hộ bn MMS_Hồ Khánh Châu nha:
Bài 4:
Gọi x là giá trị chung của 2 phân số trên.
Ta có: \(\frac{a}{b}=\frac{c}{d}=x\)
\(\Rightarrow a=x.b
\)
\(c=x.d\)
Ta lại có:
\(\frac{a+c}{b+d}=\frac{x.b+x.d}{b+d}=\frac{x.\left(b+d\right)}{b+d}=x\)
Và \(\frac{a}{b}=x\)
\(\Rightarrow\frac{a}{b}=\frac{a+c}{b+d}\)
Vậy \(\frac{a}{b}=\frac{a+c}{b+d}\)
Hk tốt nha
\(\frac{4}{3}:0,8=\frac{2}{3}:0,1x\\ \Leftrightarrow x=\frac{4}{3}:0,8:\frac{2}{3}.0,1=\frac{4}{3}:\frac{4}{5}:\frac{2}{3}.\frac{1}{10}\\ \Leftrightarrow x=\frac{4}{3}.\frac{5}{4}.\frac{3}{2}.\frac{1}{10}=\frac{5}{20}=\frac{1}{4}\)