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\(=\frac{4^5.\left(3^2\right)^4}{\left(4^2\right)^2.\left(3^3\right)^3}=\frac{4^5.3^8}{4^4.3^9}=\frac{4}{3}\)
\(=\frac{\left(2^2\right)^5\cdot\left(3^2\right)^4}{\left(2^4\right)^2\cdot\left(3^3\right)^3}\)
\(=\frac{2^{10}\cdot3^8}{2^8\cdot3^9}\)
\(=\frac{4}{3}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a.
\(\left(\frac{1}{3}\right)^2\times27=3^x\)
\(\frac{1^2}{3^2}\times3^3=3^x\)
\(3^1=3^x\)
\(x=1\)
b.
\(\frac{64}{\left(-2\right)^x}=-32\)
\(\frac{\left(-2\right)^6}{\left(-2\right)^x}=\left(-2\right)^5\)
\(\left(-2\right)^x=\frac{\left(-2\right)^6}{\left(-2\right)^5}\)
\(\left(-2\right)^x=-2\)
\(x=1\)
c.
\(3x^2-\frac{1}{2}x=0\)
\(x\times\left(3x-\frac{1}{2}\right)=0\)
TH1:
\(x=0\)
TH2:
\(3x-\frac{1}{2}=0\)
\(3x=\frac{1}{2}\)
\(x=\frac{1}{2}\div3\)
\(x=\frac{1}{2}\times\frac{1}{3}\)
\(x=\frac{1}{6}\)
Vậy x = 0 hoặc x = 1/6
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\(\frac{9^2.27^4}{3.81^3}\)=\(\frac{3^4.3^{12}}{3.3^{12}}\)=\(\frac{3^3.1}{1.1}\)=\(3^3\)
TK MIK NHA
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a.\(3^{-2}.3^2.27^x=\frac{1}{3}\)
\(\Rightarrow3^{-2+2}.\left(3^3\right)^x=\frac{1}{3}\)
\(\Rightarrow3^0.3^{3x}=3^{-1}\)
\(\Rightarrow3^{3x}=3^{-1}\)
=> 3x=-1
=> x=\(-\frac{1}{3}\)
b.\(7^{x+2}+2.7^{x-1}=345\)
\(\Rightarrow7^{x-1}.\left(7^3+2\right)=345\)
\(\Rightarrow7^{x-1}.345=345\)
=> 7x-1=345 : 345
=> 7x-1=1
=> 7x-1=70
=> x-1=0
Vậy x=1.
c.\(\left(2x-1\right)^6=\left(2x-1\right)^8\)
\(\Rightarrow\left(2x-1\right)\in\left\{-1;0;1\right\}\)
=> 2x-1=-1 hoặc 2x-1=0 hoặc 2x-1=1
=> 2x=0 hoặc 2x=1 hoặc 2x=2
=> x=0 hoặc x=\(\frac{1}{2}\) hoặc x=1
Vậy \(x\in\left\{0;\frac{1}{2};1\right\}\)
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a)
1/4:(31/16-2+1/2)+1
=1/4:(-1/16+1/2)+1
=(1/4:7/16)+1
=4/7+1
=11/7
b)
43/6:(-7/6)+65/6.(-7/6)+1/2
=-43/7+-455/36+1/2
=-4607/252
c)
1/4+11/2.5/2+-2
=23/4.5/2+-2
=115/8+-2
=99/8
d) bài 4 rất dễ bạn tự làm đi nhé
tick cho mk đi nhanh lên đó nhiên
=
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\(\frac{1}{2}+\frac{2}{3}-\frac{3}{4}+\frac{4}{5}-\frac{5}{6}+\frac{6}{7}+\frac{5}{6}-\frac{4}{5}+\frac{3}{4}-\frac{2}{3}+\frac{1}{2}\)
\(=\left(\frac{1}{2}+\frac{1}{2}+\frac{6}{7}\right)+\left(\frac{2}{3}-\frac{2}{3}\right)+\left(\frac{-3}{4}+\frac{3}{4}\right)+\left(\frac{4}{5}-\frac{4}{5}\right)+\left(\frac{-5}{6}+\frac{5}{6}\right)\)
\(=\frac{13}{7}+0+0+0+0\)
\(=\frac{13}{7}\)
\(\frac{1}{2}+\frac{2}{3}-\frac{3}{4}+\frac{4}{5}-\frac{5}{6}+\frac{6}{7}+\frac{5}{6}-\frac{4}{5}+\frac{3}{4}-\frac{2}{3}+\frac{1}{2}.\)
\(=\left(\frac{1}{2}+\frac{1}{2}\right)+\left(\frac{2}{3}-\frac{2}{3}\right)-\left(\frac{3}{4}-\frac{3}{4}\right)+\left(\frac{4}{5}-\frac{4}{5}\right)-\left(\frac{5}{6}-\frac{5}{6}\right)+\frac{6}{7}\)
\(=1+0-0+0+\frac{6}{7}\)
\(=1+\frac{6}{7}=1\frac{6}{7}\)