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Ta có:
4116 / 10290 = 7.7.7.712 - 7.2 / 7.7.7.7 30-7.5
= 12-2 / 30-5
= 10 / 25
= 2 / 5
nhớ k cho mình nha
A=4102/10255<=>2051*2/2051*5<=>A=2/5
B=2828/4242<=>1414*2/1414*3<=>B=2/3
ủng hộ nha mn
\(H=\frac{4116-14}{10290-35}=\frac{14.294-14}{35.294-35}=\frac{14.\left(294-1\right)}{35.\left(294-1\right)}=\frac{14.293}{35.293}=\frac{2}{5}\)
\(K=\frac{29.101-101}{2.19.101+4.101}=\frac{101.\left(29-1\right)}{101.\left(38+4\right)}=\frac{28}{42}=\frac{2}{3}\)
\(I=\frac{1313-1717}{303}=\frac{13.101-17.101}{3.101}=\frac{101.\left(13-17\right)}{3.101}=\frac{-4}{3}\)
\(M=\frac{12-24.3}{1-35}=\frac{12-12.2.3}{-34}=\frac{12.\left(1-6\right)}{-34}=\frac{-60}{-34}=\frac{30}{17}\)
\(H\)\(=\) \(\frac{4116-14}{10290-35}\)
\(=\) \(\frac{4102}{10255}\)
\(=\) \(\frac{4102:2051}{10255:2051}\)
\(=\) \(\frac{2}{5}\)
\(K=\frac{2929-101}{2.1919+404}\)
\(=\) \(\frac{2828}{4242}\)
\(=\) \(\frac{2828:1414}{4242:1414}\)
\(=\) \(\frac{2}{3}\)
\(M=\frac{12-24.3}{1-35}\)
\(=\) \(\frac{-60}{-34}\)
\(=\) \(\frac{60}{34}\)
\(=\) \(\frac{30}{17}\)
:D
4116 - 14/ 10290 - 35
= 4102/10255
= 4102 : 2051/10255 : 2051
= 2/5
A=\(\frac{14.294-14}{35.294-35}=\frac{14.\left(294-1\right)}{35.\left(294-1\right)}=\frac{14}{35}=\frac{2}{5}\)
ƯCLN(4116,35)=7
ƯCLN(14,10290)=14
Nên rút gọn thành: 588-1/735-5
A=4116-14/10290-35
=[14 x ( 294 -1 )]/[35 x (294-1)]
= 14/35
B =2929-101/2.1919+404
= [101 x (291-1)] / [101 x 38 + 101 x 4)]
= [ 101x (29 -1)] / [ 101 x (38+4)
= (29-1) / (38+4)
= 28/42 = 2/3
A=4116-14/10290-35=14.294-14.1/35.294-35.1=14.(291-1)/35.(294-1)=14/35=14:7/35:7=2/5
B=2929-101/2.1919+404=101.29-101.1/2.19.101+4.101=101.(29-1)/101.(2.19+4)=28/42=28:14/42:14=2/3
A= 4116-14
10290-35
= 294.14 - 14
35.294 - 35
= 294 . 14
294 . 35 ghạch 2 số 294
=14
35
= 2
5
phàn B tương tự
\(=\frac{4102}{10255}\)
4116-14/10290-35 = 2/5