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a. 5x +2 4/5 = 15
=> 5x + 14/5 = 15
=> 5x = 15 - 14/5 = 61/5
=> x = 61/5 : 5
=> x = 61/25
a)5x + 2 4/5 =15
5x+14/5=15
5x=15- 14/5
5x=71/5
x=71/5 :5
x=71
a)x+12=-25
x= (-25) -12
x= -37. Vậy x= -37
b) 30 : ( x -7 ) = 159 : 158
30 : (x-7) = 15
x - 7 = 30 : 15
x - 7= 2
x= 2+7
x = 9. Vậy x= 9
\(a,x+12=-25\)
\(x=-25-12\)
\(x=-37\)
\(b,30:\left(x-7\right)=15^9:15^8\)
\(30:\left(x-7\right)=15\)
\(x-7=30:15=2\)
\(x=2+7=9\)
(7x-11)3=25.52+200
=> (7x-11)3=800+200
=> (7x-11)3=1000
=> (7x-11)3=103
=> 7x - 11 = 10
=> 7x = 21
=> x = 3
(2x-15)5=(2x-15)3
=> (2x-15)5 - (2x-15)3 = 0
=> (2x-15)3 . [ (2x-15)2 - 1 ] = 0
=> \(\orbr{\begin{cases}\left(2x-15\right)^3=0\\\left(2x-15\right)^2-1=0\end{cases}\Rightarrow\orbr{\begin{cases}2x-15=0\\2x-15=1\end{cases}\Rightarrow}\orbr{\begin{cases}2x=15\\2x=16\end{cases}\Rightarrow}\orbr{\begin{cases}x=\frac{15}{2}\\x=8\end{cases}}}\)
Mà x thuộc N
=> x = 8
(3x-5)10=(3x-5)9
=> (3x-5)10 - (3x-5)9 = 0
=> (3x-5)9 .[ (3x-5) - 1 ] = 0
=> \(\orbr{\begin{cases}\left(3x-5\right)^9=0\\\left(3x-5\right)-1=0\end{cases}\Rightarrow\orbr{\begin{cases}3x-5=0\\3x-5=1\end{cases}\Rightarrow}\orbr{\begin{cases}3x=5\\3x=6\end{cases}\Rightarrow\orbr{\begin{cases}x=\frac{5}{3}\\x=2\end{cases}}}}\)
Mà x thuộc N
=> x = 2
a)(7x-11)^3=1000
(7x-11)^3=10^3
7x-11 =10
7x =10+11=21
x =21:7=3
\(\dfrac{4}{5}\left(\dfrac{2}{3}x-\dfrac{9}{5}\right)-\dfrac{2}{5}\cdot\dfrac{-3}{7}=\dfrac{15}{4}\)
\(\Rightarrow\dfrac{2}{5}\left(\dfrac{2}{3}x-\dfrac{9}{5}\right)-\dfrac{-6}{35}=\dfrac{15}{4}\)
\(\Rightarrow\dfrac{2}{5}\left(\dfrac{2}{3}x-\dfrac{9}{5}\right)+\dfrac{6}{35}=\dfrac{15}{4}\)
\(\Rightarrow\dfrac{2}{5}\left(\dfrac{2}{3}x-\dfrac{9}{5}\right)=\dfrac{15}{4}-\dfrac{6}{35}=\dfrac{501}{140}\)
\(\Rightarrow\dfrac{2}{3}x-\dfrac{9}{5}=\dfrac{501}{140}:\dfrac{2}{5}=\dfrac{501\cdot5}{28\cdot5\cdot2}=\dfrac{501}{56}\)
\(\Rightarrow\dfrac{2}{3}x=\dfrac{501}{56}+\dfrac{9}{5}=\dfrac{2001}{280}\)
\(\Rightarrow x=\dfrac{2001}{280}:\dfrac{2}{3}=\dfrac{2001\cdot3}{280\cdot2}=\dfrac{6003}{560}\)
-15 ( x - 2 ) + 7 ( 3 - x ) = 7
-15x + 30 + 21 - 7x = 7
-15x - 7x = 7 - 21 - 30
-22x = -44
x = ( -44 ) : ( -22)
x = 2
Vậy x = 2
-12 ( x - 5 ) + 7 ( 3 - x ) = 5
-12x + 60 + 21 - 7x = 5
-12x - 7x = 5 - 21 - 60
-19x = -76
x = ( -76 ) : (-19)
x = 4
Vậy x = 4.
# HOK TỐT #
a,x- 2/3= -1/2
x= -1/2 + 2/3
x= 1/6
b,20%.x - x +1/5 =3/4
1/5.x - x +1/5 = 3/4
1/5.x-x =3/4 - 1/5
x.(1/5 - 1)=11/20
x.-4/5 =11/20
x=11/20 : -4/5=-11/16
a) \(x-\frac{2}{3}=-\frac{1}{2}\)
\(\Leftrightarrow x=\frac{2}{3}-\frac{1}{2}\)
\(\Leftrightarrow x=\frac{1}{6}\)
b) \(20\%x-x+\frac{1}{5}=\frac{3}{4}\)
\(\Leftrightarrow\frac{1}{5}x-x=\frac{3}{4}-\frac{1}{5}\)
\(\Leftrightarrow-\frac{4}{5}x=\frac{11}{5}\)
\(\Leftrightarrow x=\frac{11}{5}:\left(-\frac{4}{5}\right)\)
\(\Leftrightarrow x=-\frac{11}{4}\)
\(\frac{3}{5}.x-x=\frac{-4}{15}\)
<=>\(x.\left(\frac{3}{5}-1\right)=\frac{-4}{15}\)
<=>\(\frac{-2}{5}.x=\frac{-4}{15}\)
<=>\(x=\frac{-4}{15}:\frac{-2}{5}\)
<=>\(x=\frac{2}{3}\)
vậy \(x=\frac{2}{3}\)
Ta có:\(\frac{3}{5}.x-x=-\frac{4}{15}\)
\(\left(\frac{3}{5}-1\right).x=-\frac{4}{15}\)
\(\left(\frac{3}{5}-\frac{5}{5}\right).x=-\frac{4}{15}\)
\(\left(-\frac{2}{5}\right).x=-\frac{4}{15}\)
\(x=-\frac{4}{15}:\left(-\frac{2}{5}\right)\)
\(x=-\frac{4}{15}.\left(-\frac{5}{2}\right)\)
\(x=\frac{\left(-4\right).\left(-5\right)}{15.2}\)
\(x=\frac{20}{30}=\frac{2}{3}\)
\(\frac{3}{x+5}=15\%\)
\(\frac{3}{x+5}=\frac{15}{100}\)
\(\frac{3}{x+5}=\frac{3}{20}\)
\(3\cdot(x+5)=3\cdot20\)
\(3\cdot(x+5)=60\)
\(x+5=60:3\)
\(x+5=20\)
\(x=15\)
= x+5 -3=15%