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\(\frac{37-x}{x+13}=\frac{3}{7}\)
\(\Leftrightarrow3.\left(x+13\right)=7.\left(37-x\right)\)
\(\Leftrightarrow3.x+13.3=7.37-7.x\)
\(\Leftrightarrow3x+39=-7x+259\)
\(\Leftrightarrow3x+7x=259-39\)
\(\Leftrightarrow10x=220\)
\(\Leftrightarrow x=22\)
\(\frac{4}{7}=\frac{7}{x^2}\)
\(\Leftrightarrow4x^2=7.7\)
\(\Leftrightarrow\left(2x\right)^2=49\)
\(\Leftrightarrow\orbr{\begin{cases}2x=7\\2x=-7\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=\frac{7}{2}\\x=-\frac{7}{2}\end{cases}}\)
a, <=> 7(37-x)=3(x+13)
<=> x =22
b, <=> (x+1)(x-1)=15
<=> x^2-1=15 <=> x^2=16 <=> x= +_4
\(\Leftrightarrow7\left(37-x\right)=3\left(x+13\right)\Leftrightarrow259-7x=3x+39\Leftrightarrow259-39=3x+7x\)
\(10x=220\Leftrightarrow x=22\)
(37-x) . 7 =3. (x+13)
=>259 -7x=3x+39
=>.259-39=3x+7x
=>220=10x
=>x=22
\(\frac{37-x}{x+13}=\frac{3}{7}\)
=> 3.(x+13)=7.(37-x)
=> 3x+39= 259-7x
=> 3x+7x=259-39
=> 10x= 220
=> x=22
a) 0,4:x=x:0,9
0,4.0,9=x2
0,36 =x2
\(\sqrt{0,36}\)=x
0,6 =x
\(\frac{37-x}{3}=\frac{x-13}{7}\)
\(\Rightarrow7\left(37-x\right)=3\left(x-13\right)\)
\(\Leftrightarrow259-7x=3x-39\)
\(\Leftrightarrow259+39=3x+7x\)
\(\Leftrightarrow298=10x\)
\(\Leftrightarrow x=29.8\)
\(\frac{37-x}{3}=\frac{x-13}{7}\)
\(\Rightarrow7\left(37-x\right)=3\left(x-13\right)\)
\(\Rightarrow259-7x=3x-39\)
\(\Rightarrow259+39=3x+7x\)
\(\Rightarrow298=10x\)
\(\Rightarrow x=\frac{298}{10}=\frac{149}{5}\)