Question

[tran thi thu hieu]

\(\frac{3}{4}+\frac{1}{4}\div\left(\frac{-2}{3}\right)-\left(-5\right)\)

\(12\cdot\left(\frac{2}{5}-\frac{5}{6}\right)^2\)

\(\left(-2\right)^2+\sqrt{36}-\sqrt{9}+\sqrt{25}\)

\(\left(9\frac{3}{4}\div3.4\cdot2\frac{7}{34}\right)\div\left(-1\frac{9}{16}\right)\)

\(\frac{\sqrt{3^2}+\sqrt{39^2}}{\sqrt{91^2}-\sqrt{\left(-7\right)^2}}\)

Answer 1

[Nguyễn Quang Trung]

câu  nào bạn không làm đc

Answer 2

[Minh Hiền]

\(\frac{3}{4}+\frac{1}{4}:\left(-\frac{2}{3}\right)-\left(-5\right)\)

\(=\frac{3}{4}+\frac{1}{4}.\left(-\frac{3}{2}\right)+5\)

\(=\frac{3}{4}-\frac{3}{8}+5\)

\(=\frac{3}{8}+5=\frac{43}{8}\)

\(12.\left(\frac{2}{5}-\frac{5}{6}\right)^2=12.\left(-\frac{13}{30}\right)^2=12.\frac{169}{900}=\frac{169}{75}\)

\(\left(-2\right)^2+\sqrt{36}-\sqrt{9}+\sqrt{25}=4+6-3+5=12\)

\(\left(9\frac{3}{4}:3.4.2\frac{7}{34}\right):\left(-1\frac{9}{16}\right)=\left(\frac{39}{4}:3.4.\frac{75}{34}\right):\left(-\frac{25}{16}\right)=\frac{975}{34}.\left(-\frac{16}{25}\right)=-\frac{312}{17}\)

\(\frac{\sqrt{3^2}+\sqrt{39^2}}{\sqrt{91^2}-\sqrt{\left(-7\right)^2}}=\frac{3+39}{91-7}=\frac{42}{84}=\frac{1}{2}\)