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a) \(\frac{34}{13}=2\frac{8}{13}\)
Vì 2 > 1 nên \(2\frac{8}{13}>1\frac{7}{9}\)
hay \(\frac{34}{13}>1\frac{7}{9}\)
b) \(\frac{7}{9}=1-\frac{2}{9}\)
\(\frac{13}{15}=1-\frac{2}{15}\)
Vì \(\frac{2}{9}>\frac{2}{15}\) nên \(\frac{7}{9}< \frac{13}{15}\)
a) Ta có:
\(1\frac{7}{9}=\frac{16}{9}=\frac{208}{117}\)
\(\frac{34}{13}=\frac{306}{117}\)
Vì \(306>208\)
\(\Rightarrow\frac{306}{117}>\frac{208}{117}\)
\(\Rightarrow\frac{34}{13}>1\frac{7}{9}\)
b) Ta có:
\(\frac{7}{9}=\frac{35}{45}\)
\(\frac{13}{15}=\frac{39}{45}\)
Vì \(39>35\)
\(\Rightarrow\frac{39}{45}>\frac{35}{45}\)
\(\Rightarrow\frac{13}{15}>\frac{7}{9}\)
1. \(\frac{5}{9}.\frac{7}{13}+\frac{5}{9}.\frac{9}{13}-\frac{5}{9}.\frac{3}{13}\)
= \(\frac{5}{9}\) .(\(\frac{7}{13}+\frac{9}{13}-\frac{3}{13}\) )
= \(\frac{5}{9}\) . 1 = \(\frac{5}{9}\)
C = \(\frac{3}{7}\cdot\frac{9}{26}-\frac{1}{14}\cdot\frac{1}{13}-\frac{1}{7}\)
C = \(\frac{1}{7}\cdot3\cdot\frac{9}{26}-\frac{1}{7}\cdot\frac{1}{2}\cdot\frac{1}{13}-\frac{1}{7}\)
C = \(\frac{1}{7}\cdot\frac{27}{26}-\frac{1}{7}\cdot\frac{1}{26}-\frac{1}{7}\)
C = \(\frac{1}{7}\left(\frac{27}{26}-\frac{1}{26}-1\right)\)
C = \(\frac{1}{7}\left(1-1\right)\)
C = 0
Chúc bn học tốt
\(\Leftrightarrow\frac{34}{9}.x:\left(9+\frac{13}{9}\right)=34+\frac{1}{4}\)
\(\Leftrightarrow\frac{34}{9}.x:\frac{94}{9}=\frac{137}{4}\)
\(\Leftrightarrow\frac{17}{57}.x=\frac{137}{4}\Rightarrow x=\frac{17.4}{57.137}\)(tu tinh )