\(\frac{12}{25}.\left(-38,2\right)-\frac{12}{25}.61,8\)

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17 tháng 7 2016

=\(\frac{12}{25}.\left(-38,2-61,8\right)\)

=\(\frac{12}{25}.\left(-100\right)\)

=\(-48\)

17 tháng 7 2016

= 12/25 . (-38,2 - 61,8)

=  12/25 . (-100)

=  -48

5 tháng 12 2018

a, \(\frac{3}{5}\left(2x-\frac{1}{3}\right)+\frac{4}{15}=\frac{12}{30}\)

\(\Leftrightarrow\frac{3}{5}\left(2x-\frac{1}{3}\right)=\frac{2}{15}\)

\(\Leftrightarrow2x-\frac{1}{3}=\frac{2}{9}\)

\(\Leftrightarrow2x=\frac{5}{9}\)

\(\Leftrightarrow x=\frac{5}{18}\)

b,\(\left(-0,2\right)^x=\frac{1}{25}\)

\(\Leftrightarrow\left(\frac{-1}{5}\right)^x=\left(\frac{-1}{5}\right)^2\)

\(\Leftrightarrow x=2\)

c,\(\left|x-1\right|-\frac{3}{12}=\left(-\frac{1}{2}\right)^2\)

\(\Leftrightarrow\left|x-1\right|-\frac{3}{12}=\frac{1}{4}\)

\(\Leftrightarrow\left|x-1\right|=\frac{1}{2}\)

\(\Leftrightarrow\orbr{\begin{cases}x-1=\frac{1}{2}\\x-1=-\frac{1}{2}\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=\frac{3}{2}\\x=\frac{1}{2}\end{cases}}\)

5 tháng 12 2018

\(a,\frac{3}{5}\left(2x-\frac{1}{3}\right)=\frac{12}{30}-\frac{4}{15}\)

\(\frac{3}{5}\left(2x-\frac{1}{3}\right)=\frac{2}{15}\)

\(2x-\frac{1}{3}=\frac{2}{9}\)

\(x=\frac{5}{18}\)

\(b,\left(-0,2\right)^x=\frac{1}{25}\)

\(\left(-0,2\right)^x=\left(-\frac{1}{5}\right)^2\)

\(\left(-0,2\right)^x=\left(-0,2\right)^2\)

\(x=2\)

c,/x-1/=1/2 

Nếu 
\(x-1\ge0\)

\(x\ge1\)

suy ra x-1=1/2

         x=3/2(thỏa mãn điều kiện )

nếu \(x-1\le0\)

   \(x\le1\)

suy ra x-1=-1/2

           x=1/2 (thỏa mãn điều kiện )

Vậy ...

nha !!!

11 tháng 12 2019

a) \(\frac{15}{12}+\frac{5}{13}-\frac{3}{12}-\frac{18}{13}=\left(\frac{15}{12}-\frac{3}{12}\right)+\left(\frac{5}{13}-\frac{18}{13}\right)\)

                                                     \(=1+\left(-1\right)\)

                                                     \(=0\)

b) \(\frac{11}{24}-\frac{5}{41}+\frac{13}{24}+0,5-\frac{36}{41}=\left(\frac{11}{24}+\frac{13}{24}\right)+\left(-\frac{5}{41}-\frac{36}{41}\right)+0,5\)

                                                                    \(=1+\left(-1\right)+0,5\)

                                                                    \(=0,5\)

_Học tốt nha_

11 tháng 12 2019

a, \(\frac{15}{12}\)\(\frac{5}{13}\)\(\frac{3}{12}\)-\(\frac{18}{13}\)

\(\frac{5}{4}\)\(\frac{5}{13}\) - \(\frac{1}{4}\) - \(\frac{18}{13}\)

\(\left(\frac{5}{4}-\frac{1}{4}\right)\)\(\left(\frac{5}{13}-\frac{18}{13}\right)\)

= 1 - 1 = 0

b, \(\frac{11}{24}\)\(\frac{5}{41}\)\(\frac{13}{24}\)+ 0,5 - \(\frac{36}{41}\)

\(\left(\frac{11}{24}+\frac{13}{24}\right)\)\(\left(\frac{5}{41}+\frac{36}{41}\right)\)+ 0,5

= 1 - 1 + 0,5 = 0,5

c,  \(\left(-\frac{3}{4}+\frac{2}{3}\right):\frac{5}{11}+\left(-\frac{1}{4}+\frac{1}{3}\right):\frac{5}{11}\)

=\(\left(-\frac{3}{4}+\frac{2}{3}\right).\frac{11}{5}+\left(-\frac{1}{4}+\frac{1}{3}\right).\frac{5}{11}\)

\(\frac{11}{5}.\left(-\frac{3}{4}+\frac{2}{3}-\frac{1}{4}+\frac{1}{3}\right)\)

\(\frac{11}{5}.\left[\left(-\frac{3}{4}-\frac{1}{4}\right)+\left(\frac{2}{3}+\frac{1}{3}\right)\right]\)

=  \(\frac{11}{5}.\left[\left(-1\right)+1\right]\)

= 0

d, \(\left(-3\right)^2.\left(\frac{3}{4}-0,25\right)-\left(3\frac{1}{2}-1\frac{1}{2}\right)\)

\(9.\left(0,75-0,25\right)-2\)

= 9. 0,5 - 2 = 2,5

e, \(\frac{13}{25}+\frac{6}{41}-\frac{38}{25}+\frac{35}{41}-\frac{1}{2}\)

\(\left(\frac{13}{25}-\frac{38}{25}\right)+\left(\frac{6}{41}+\frac{35}{41}\right)-\frac{1}{2}\)

= -1 + 1 - \(\frac{1}{2}\)

\(-\frac{1}{2}\)

27 tháng 8 2017

Gọi 1/4 số a là 0,25 . Ta có :

                   a . 3 - a . 0,25 = 147,07

                   a . (3 - 0,25) = 147,07 ( 1 số nhân 1 hiệu )

                      a . 2,75 = 147,07

                         a = 147,07 : 2,75

                          a = 53,48

2 tháng 9 2017

Phan Hoàng Mai

Tính : 

\(\left(-0,5-\frac{3}{5}\right):\left(-\frac{22}{25}\right)+\left(\frac{2}{25}-1,08\right).\frac{3}{8}-72:12^2\)

\(=\left(-\frac{5}{10}-\frac{3}{5}\right):\frac{-22}{25}+\left(\frac{2}{25}-\frac{108}{100}\right).\frac{3}{8}-72:144\)

\(=\left(-\frac{5}{10}-\frac{6}{10}\right).\frac{-25}{22}+\left(\frac{8}{100}-\frac{108}{100}\right).\frac{3}{8}-\frac{1}{2}\)

\(=\frac{-11}{10}.\frac{-25}{22}+\left(-1\right).\frac{3}{8}-\frac{1}{2}\)

\(=\frac{\left(-11\right).\left(-25\right)}{10.22}+\frac{-3}{8}-\frac{1}{2}\)

\(=\frac{5}{4}+\frac{-3}{8}-\frac{1}{2}\)

\(=\frac{10}{8}+\frac{-3}{8}-\frac{4}{8}\)

\(=\frac{3}{8}\)

Chúc bạn học tốt!!!

2 tháng 9 2017

\(\left(-0,5-\frac{3}{5}\right):\left(-\frac{22}{25}\right)+\left(\frac{2}{25}-1,08\right)\cdot\frac{3}{8}-72:12^2\)

=\(\left(-\frac{1}{2}-\frac{3}{5}\right):\left(-\frac{22}{25}\right)+\left(\frac{2}{25}-\frac{27}{25}\right)\cdot\frac{3}{8}-\frac{72}{144}\)

=\(\left(-\frac{11}{10}.\left(-\frac{25}{22}\right)\right)-1\cdot\frac{3}{8}-\frac{1}{2}\)

\(\frac{5}{4}-\frac{3}{8}-\frac{1}{2}\)

\(\frac{10}{8}-\frac{3}{8}-\frac{4}{8}=\frac{3}{8}\)

2 tháng 9 2017

\(\left(-0,5-\dfrac{3}{5}\right):\left(\dfrac{-22}{25}\right)+\left(\dfrac{2}{25}-1,08\right).\dfrac{3}{8}-72:12^2\)

\(=\left(\dfrac{-1}{2}-\dfrac{3}{5}\right):\left(\dfrac{-22}{25}\right)+\left(\dfrac{2}{25}-\dfrac{27}{25}\right).\dfrac{3}{8}-\dfrac{72}{144}\)

\(=\left[\dfrac{-11}{10}.\dfrac{-25}{22}\right]-1.\dfrac{3}{8}-\dfrac{1}{2}\)

\(=\dfrac{5}{4}-\dfrac{3}{8}-\dfrac{1}{2}\)

\(=\dfrac{10}{8}-\dfrac{3}{8}-\dfrac{4}{8}\)

\(=\dfrac{3}{8}\)

12 tháng 8 2019

Tính:

a) \(-3\frac{3}{4}+\left(-\frac{10}{25}\right)+\left(-\frac{6}{12}\right)\)

\(=\left(-\frac{15}{4}\right)+\left(-\frac{10}{25}\right)+\left(-\frac{6}{12}\right)\)

\(=\left(-\frac{83}{20}\right)+\left(-\frac{6}{12}\right)\)

\(=-\frac{93}{20}.\)

b) \(-0,6-\left(-\frac{4}{9}\right)-\frac{16}{15}\)

\(=\left(-\frac{3}{5}\right)-\left(-\frac{4}{9}\right)-\frac{16}{15}\)

\(=\left(-\frac{7}{45}\right)-\frac{16}{15}\)

\(=-\frac{11}{9}.\)

Chúc bạn học tốt!

23 tháng 7 2016

\(\left(\frac{12}{25}\right)^x=\left(\frac{5}{3}\right)^{-2}-\left(-\frac{3}{5}\right)^4\)

\(\left(\frac{12}{25}\right)^x=\frac{144}{625}\)

\(\left(\frac{12}{25}\right)^x=\left(\frac{12}{25}\right)^2\)

\(x=2\)

Chúc bạn học tốt ^^

4 tháng 10 2021

yutyugubhujyikiu

19 tháng 12 2018

\(a,=\left(\frac{15}{12}-\frac{3}{12}\right)+\left(\frac{5}{13}-\frac{18}{13}\right)\)

\(=1+-1\)

\(=0\)