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a, \(\frac{3}{5}\left(2x-\frac{1}{3}\right)+\frac{4}{15}=\frac{12}{30}\)
\(\Leftrightarrow\frac{3}{5}\left(2x-\frac{1}{3}\right)=\frac{2}{15}\)
\(\Leftrightarrow2x-\frac{1}{3}=\frac{2}{9}\)
\(\Leftrightarrow2x=\frac{5}{9}\)
\(\Leftrightarrow x=\frac{5}{18}\)
b,\(\left(-0,2\right)^x=\frac{1}{25}\)
\(\Leftrightarrow\left(\frac{-1}{5}\right)^x=\left(\frac{-1}{5}\right)^2\)
\(\Leftrightarrow x=2\)
c,\(\left|x-1\right|-\frac{3}{12}=\left(-\frac{1}{2}\right)^2\)
\(\Leftrightarrow\left|x-1\right|-\frac{3}{12}=\frac{1}{4}\)
\(\Leftrightarrow\left|x-1\right|=\frac{1}{2}\)
\(\Leftrightarrow\orbr{\begin{cases}x-1=\frac{1}{2}\\x-1=-\frac{1}{2}\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=\frac{3}{2}\\x=\frac{1}{2}\end{cases}}\)
\(a,\frac{3}{5}\left(2x-\frac{1}{3}\right)=\frac{12}{30}-\frac{4}{15}\)
\(\frac{3}{5}\left(2x-\frac{1}{3}\right)=\frac{2}{15}\)
\(2x-\frac{1}{3}=\frac{2}{9}\)
\(x=\frac{5}{18}\)
\(b,\left(-0,2\right)^x=\frac{1}{25}\)
\(\left(-0,2\right)^x=\left(-\frac{1}{5}\right)^2\)
\(\left(-0,2\right)^x=\left(-0,2\right)^2\)
\(x=2\)
c,/x-1/=1/2
Nếu
\(x-1\ge0\)
\(x\ge1\)
suy ra x-1=1/2
x=3/2(thỏa mãn điều kiện )
nếu \(x-1\le0\)
\(x\le1\)
suy ra x-1=-1/2
x=1/2 (thỏa mãn điều kiện )
Vậy ...
nha !!!
a) \(\frac{15}{12}+\frac{5}{13}-\frac{3}{12}-\frac{18}{13}=\left(\frac{15}{12}-\frac{3}{12}\right)+\left(\frac{5}{13}-\frac{18}{13}\right)\)
\(=1+\left(-1\right)\)
\(=0\)
b) \(\frac{11}{24}-\frac{5}{41}+\frac{13}{24}+0,5-\frac{36}{41}=\left(\frac{11}{24}+\frac{13}{24}\right)+\left(-\frac{5}{41}-\frac{36}{41}\right)+0,5\)
\(=1+\left(-1\right)+0,5\)
\(=0,5\)
_Học tốt nha_
a, \(\frac{15}{12}\)+ \(\frac{5}{13}\)- \(\frac{3}{12}\)-\(\frac{18}{13}\)
= \(\frac{5}{4}\)+ \(\frac{5}{13}\) - \(\frac{1}{4}\) - \(\frac{18}{13}\)
= \(\left(\frac{5}{4}-\frac{1}{4}\right)\)+ \(\left(\frac{5}{13}-\frac{18}{13}\right)\)
= 1 - 1 = 0
b, \(\frac{11}{24}\)- \(\frac{5}{41}\)+ \(\frac{13}{24}\)+ 0,5 - \(\frac{36}{41}\)
= \(\left(\frac{11}{24}+\frac{13}{24}\right)\)- \(\left(\frac{5}{41}+\frac{36}{41}\right)\)+ 0,5
= 1 - 1 + 0,5 = 0,5
c, \(\left(-\frac{3}{4}+\frac{2}{3}\right):\frac{5}{11}+\left(-\frac{1}{4}+\frac{1}{3}\right):\frac{5}{11}\)
=\(\left(-\frac{3}{4}+\frac{2}{3}\right).\frac{11}{5}+\left(-\frac{1}{4}+\frac{1}{3}\right).\frac{5}{11}\)
= \(\frac{11}{5}.\left(-\frac{3}{4}+\frac{2}{3}-\frac{1}{4}+\frac{1}{3}\right)\)
= \(\frac{11}{5}.\left[\left(-\frac{3}{4}-\frac{1}{4}\right)+\left(\frac{2}{3}+\frac{1}{3}\right)\right]\)
= \(\frac{11}{5}.\left[\left(-1\right)+1\right]\)
= 0
d, \(\left(-3\right)^2.\left(\frac{3}{4}-0,25\right)-\left(3\frac{1}{2}-1\frac{1}{2}\right)\)
= \(9.\left(0,75-0,25\right)-2\)
= 9. 0,5 - 2 = 2,5
e, \(\frac{13}{25}+\frac{6}{41}-\frac{38}{25}+\frac{35}{41}-\frac{1}{2}\)
= \(\left(\frac{13}{25}-\frac{38}{25}\right)+\left(\frac{6}{41}+\frac{35}{41}\right)-\frac{1}{2}\)
= -1 + 1 - \(\frac{1}{2}\)
= \(-\frac{1}{2}\)
Phan Hoàng Mai
Tính :
\(\left(-0,5-\frac{3}{5}\right):\left(-\frac{22}{25}\right)+\left(\frac{2}{25}-1,08\right).\frac{3}{8}-72:12^2\)
\(=\left(-\frac{5}{10}-\frac{3}{5}\right):\frac{-22}{25}+\left(\frac{2}{25}-\frac{108}{100}\right).\frac{3}{8}-72:144\)
\(=\left(-\frac{5}{10}-\frac{6}{10}\right).\frac{-25}{22}+\left(\frac{8}{100}-\frac{108}{100}\right).\frac{3}{8}-\frac{1}{2}\)
\(=\frac{-11}{10}.\frac{-25}{22}+\left(-1\right).\frac{3}{8}-\frac{1}{2}\)
\(=\frac{\left(-11\right).\left(-25\right)}{10.22}+\frac{-3}{8}-\frac{1}{2}\)
\(=\frac{5}{4}+\frac{-3}{8}-\frac{1}{2}\)
\(=\frac{10}{8}+\frac{-3}{8}-\frac{4}{8}\)
\(=\frac{3}{8}\)
Chúc bạn học tốt!!!
\(\left(-0,5-\frac{3}{5}\right):\left(-\frac{22}{25}\right)+\left(\frac{2}{25}-1,08\right)\cdot\frac{3}{8}-72:12^2\)
=\(\left(-\frac{1}{2}-\frac{3}{5}\right):\left(-\frac{22}{25}\right)+\left(\frac{2}{25}-\frac{27}{25}\right)\cdot\frac{3}{8}-\frac{72}{144}\)
=\(\left(-\frac{11}{10}.\left(-\frac{25}{22}\right)\right)-1\cdot\frac{3}{8}-\frac{1}{2}\)
= \(\frac{5}{4}-\frac{3}{8}-\frac{1}{2}\)
= \(\frac{10}{8}-\frac{3}{8}-\frac{4}{8}=\frac{3}{8}\)
\(\left(-0,5-\dfrac{3}{5}\right):\left(\dfrac{-22}{25}\right)+\left(\dfrac{2}{25}-1,08\right).\dfrac{3}{8}-72:12^2\)
\(=\left(\dfrac{-1}{2}-\dfrac{3}{5}\right):\left(\dfrac{-22}{25}\right)+\left(\dfrac{2}{25}-\dfrac{27}{25}\right).\dfrac{3}{8}-\dfrac{72}{144}\)
\(=\left[\dfrac{-11}{10}.\dfrac{-25}{22}\right]-1.\dfrac{3}{8}-\dfrac{1}{2}\)
\(=\dfrac{5}{4}-\dfrac{3}{8}-\dfrac{1}{2}\)
\(=\dfrac{10}{8}-\dfrac{3}{8}-\dfrac{4}{8}\)
\(=\dfrac{3}{8}\)
Tính:
a) \(-3\frac{3}{4}+\left(-\frac{10}{25}\right)+\left(-\frac{6}{12}\right)\)
\(=\left(-\frac{15}{4}\right)+\left(-\frac{10}{25}\right)+\left(-\frac{6}{12}\right)\)
\(=\left(-\frac{83}{20}\right)+\left(-\frac{6}{12}\right)\)
\(=-\frac{93}{20}.\)
b) \(-0,6-\left(-\frac{4}{9}\right)-\frac{16}{15}\)
\(=\left(-\frac{3}{5}\right)-\left(-\frac{4}{9}\right)-\frac{16}{15}\)
\(=\left(-\frac{7}{45}\right)-\frac{16}{15}\)
\(=-\frac{11}{9}.\)
Chúc bạn học tốt!
\(\left(\frac{12}{25}\right)^x=\left(\frac{5}{3}\right)^{-2}-\left(-\frac{3}{5}\right)^4\)
\(\left(\frac{12}{25}\right)^x=\frac{144}{625}\)
\(\left(\frac{12}{25}\right)^x=\left(\frac{12}{25}\right)^2\)
\(x=2\)
Chúc bạn học tốt ^^
\(a,=\left(\frac{15}{12}-\frac{3}{12}\right)+\left(\frac{5}{13}-\frac{18}{13}\right)\)
\(=1+-1\)
\(=0\)
=\(\frac{12}{25}.\left(-38,2-61,8\right)\)
=\(\frac{12}{25}.\left(-100\right)\)
=\(-48\)
= 12/25 . (-38,2 - 61,8)
= 12/25 . (-100)
= -48