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\(=\frac{19}{4}+\left(-0.37\right)+\frac{1}{8}+\left(-1.28\right)+\left(-2.5\right)+\frac{37}{12}\)\(\frac{37}{12}\)
\(=\left(\frac{19}{4}+\frac{1}{8}+\frac{37}{12}\right)+\left(\left(-0.37\right)+\left(-1.28\right)+\left(-2.5\right)\right)\)
\(=\frac{191}{24}+\left(-\frac{83}{20}\right)\)
\(=\frac{457}{120}\)
\(\frac{10}{18}+\frac{4}{9}+\frac{26}{10}+\frac{12}{5}+\frac{9}{15}\)
\(=\frac{5}{9}+\frac{4}{9}+\frac{13}{5}+\frac{12}{5}+\frac{3}{5}\)
\(=\left(\frac{5}{9}+\frac{4}{9}\right)+\left(\frac{13}{5}+\frac{12}{5}+\frac{3}{5}\right)\)
\(=1+\frac{28}{5}\)
\(=\frac{33}{5}\)
Ta có:
a) \(\frac{10}{18}+\frac{4}{9}+\frac{26}{10}+\frac{12}{5}+\frac{9}{15}=\frac{5}{9}+\frac{4}{9}+\frac{13}{5}+\frac{12}{5}+\frac{9}{15}=1+1+\frac{9}{15}=1\frac{9}{15}\)
b)\(\frac{10}{18}+\frac{4}{9}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}+\frac{1}{128}=\left(\frac{5}{9}+\frac{4}{9}\right)+\left(\frac{16}{128}+\frac{8}{128}+\frac{4}{128}+\frac{2}{128}+\frac{1}{128}\right)\)
\(=1+\frac{31}{128}=1\frac{31}{128}\)
a) \(1284-16401:231+58\) x\(11=1284-71+638\)
\(=1851\)
b)\(\frac{7}{4}+1\frac{1}{2}\)x \(1\frac{3}{2}:\frac{1}{4}=\frac{7}{4}+15\)
\(=\frac{67}{4}\)
c)\(2\frac{1}{4}+1\frac{2}{5}+\frac{4}{20}\)\(=\frac{9}{4}+\frac{7}{5}+\frac{1}{5}\)
\(=\frac{77}{20}\)
d)\(\left(\frac{12}{5}+\frac{2}{3}-\frac{11}{4}\right):\frac{3}{4}=\frac{19}{60}:\frac{3}{4}\)
\(=\frac{19}{60}\)x \(\frac{4}{3}\)
\(=\frac{19}{45}\)
= 2/21
=9/5
=37/6:\(6\frac{1}{6}\)
=79/20: tự đổi nhe bạn
=3/5__________-
\(\frac{4}{15}x\frac{5}{14}=\frac{4x5}{15x14}=\frac{2x1}{3x7}=\frac{2}{21}\)
\(\frac{3}{4}:\frac{5}{12}=\frac{3}{4}x\frac{12}{5}=\frac{3x12}{4x5}=\frac{3x3}{1x5}=\frac{9}{5}=1,8\)
\(\frac{7}{2}+\frac{8}{3}=\frac{7x3}{2x3}+\frac{8x2}{3x2}=\frac{21}{6}+\frac{16}{6}=\frac{21+16}{6}=\frac{37}{6}\)
\(\frac{12}{2}+2,5+2-4\)
= 6 + 2,5 + 2 - 4
= 8,5 + 2 - 4
= 10,5 - 4
= 6,5
12/2+2,5+2-4
=6+2,5+2-4
=6,5