Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Ta có:
\(-\frac{3}{7}+x=\frac{1}{3}\)
=>\(x-\frac{3}{7}=\frac{1}{3}\)
=>\(x=\frac{1}{3}+\frac{3}{7}=\frac{16}{21}\)
Vậy......
3x/2.5 + 3x/5.8 + 3x/8.11 + 3x/11.14 = 1/21
=> x . ( 3/2.5 + 3/5.8 + 3/8.11 + 3/11.14 ) = 1/21
=> x . ( 1/2.5 + 1/5.8 + 1/8.11 + 1/11.14 ) = 1/21
x . ( 1/2 - 1/5 + 1/5 - 1/8 + 1/8 - 1/11 + 1/11 - 1/14 ) = 1/21
x . ( 1/2 - 1/14 ) = 1/21
x . 3/7 = 1/21
x = 1/21 : 3/7
=> x = 1/9
\(\frac{3x}{2\cdot5}+\frac{3x}{5\cdot8}+\frac{3x}{8\cdot11}+\frac{3x}{11\cdot14}=\frac{1}{21}\)
<=> \(x\left(\frac{3}{2\cdot5}+\frac{3}{5\cdot8}+\frac{3}{8\cdot11}+\frac{3}{11\cdot14}\right)=\frac{1}{21}\)
<=> \(x\left(\frac{1}{2}-\frac{1}{5}+\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+\frac{1}{11}-\frac{1}{14}\right)=\frac{1}{21}\)
<=> \(x\left(\frac{1}{2}-\frac{1}{14}\right)=\frac{1}{21}\)
<=> \(x\cdot\frac{3}{7}=\frac{1}{21}\)
<=> \(x=\frac{1}{9}\)
2
\(\text{a) }\left(\frac{1}{1.2.3}+\frac{1}{2.3.4}+.....+\frac{1}{98.99.100}\right)x=-3\)
\(\Rightarrow\frac{1}{2}\left(\frac{1}{1.2}-\frac{1}{2.3}+\frac{1}{2.3}-\frac{1}{3.4}+.....+\frac{1}{98.99}-\frac{1}{99.100}\right)x=-3\)
\(\Rightarrow\frac{1}{2}\left(\frac{1}{1.2}-\frac{1}{99.100}\right)x=-3\)
\(\Rightarrow\frac{1}{2}\left(\frac{1}{2}-\frac{1}{9900}\right)x=-3\)
\(\Rightarrow\frac{1}{2}.\left(\frac{4950}{9900}-\frac{1}{9900}\right)x=-3\)
\(\Rightarrow\left(\frac{1}{2}.\frac{4949}{9900}\right).x=-3\)
\(\Rightarrow\frac{4949}{19800}x=-3\)
\(\Rightarrow x=\left(-3\right).\frac{19800}{4949}\)
\(\Rightarrow x=\frac{-59400}{4949}\)
P/s : ko chắc nha
<=> -7(x-34)=-21x <=> -7x+238+21x=0 <=>14x=-238 => x=-17
ĐS: x=-17
mk k biet xin loi ban nha!!!!!
mk k biet xin loi ban nha!!!!!
mk k biet xin loi ban nha!!!!!
mk k biet xin loi ban nha!!!!!