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I call the number of students didn't take part in Mathemas Competition in class A & B are a & b respectively
(with condition: a & b \(\in\)N*)
,From the theme, we have: \(\frac{1}{3}b+a=\frac{1}{5}a+b\)(Because rhe number of students in 2 class is the same)
\(\Leftrightarrow\frac{b}{3}-b+a-\frac{a}{5}=0\Leftrightarrow\left(-\frac{2b}{3}\right)+\frac{4a}{5}=0\)
\(\Leftrightarrow\frac{4a}{5}-\frac{2b}{3}=0\Leftrightarrow\frac{12a-10b}{15}=0\Leftrightarrow12a=10b\)
\(\Rightarrow\frac{a}{b}=\frac{10}{12}=\frac{5}{6}\)
So the ratio of the number of student didn't take part of Class A & B is \(\frac{5}{6}.\)