Câu hỏi của Cuong Vuduy

Question

E-(2.x²-5.x.y²+3.y³)=5.x²+6.x.y²-8.x³

An Nguyễn · Accepted Answer

=> $E-2x^2+5xy^2-3y^3=5x^2+6xy^2-8x^3$

=> $-2x^2+5xy^2-3y^3-5x^2-6xy^2+8x^3=E$

=> $\left(-2x^2-5x^2\right)+\left(5xy^2-6xy^2\right)-3y^3+8x^2=E$

=> $-7x^2+\left(-1xy^2\right)-3y^2+8x^3=E$

=> $E=-7x^2-1xy^2-3y^2+8x^3$

Vậy....................

Câu trả lời:

=> $E-2x^2+5xy^2-3y^3=5x^2+6xy^2-8x^3$

=> $-2x^2+5xy^2-3y^3-5x^2-6xy^2+8x^3=E$

=> $\left(-2x^2-5x^2\right)+\left(5xy^2-6xy^2\right)-3y^3+8x^2=E$

=> $-7x^2+\left(-1xy^2\right)-3y^2+8x^3=E$

=> $E=-7x^2-1xy^2-3y^2+8x^3$

Vậy....................