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11/32=0,34375;16/49=0.3265306122
vay 11/32 > 16/49
58/89=0,6516853933;36/53=0,679246283
vay 58/89 < 36/53
\(\frac{58}{89}\)=0.651685393
\(\frac{36}{53}\)=0.679245283
vì 0.679245283 > 0.651685393
nên\(\frac{58}{89}\)<\(\frac{36}{53}\)
\(\frac{58}{89}\)& \(\frac{36}{53}\)
Ta có :
\(\frac{58}{89}\)= \(\frac{58.53}{89.53}\)=\(\frac{3074}{4717}\) ; \(\frac{36}{53}\)=\(\frac{36.89}{53.89}\)=\(\frac{3204}{4717}\)
Vậy \(\frac{58}{89}\)< \(\frac{36}{53}\)
\(\frac{58}{63}\)& \(\frac{36}{55}\)
Ta có:
\(\frac{58}{63}\)=\(\frac{58.55}{63.55}\)=\(\frac{3190}{3465}\) ; \(\frac{36}{55}\)=\(\frac{36.63}{55.63}\)=\(\frac{2268}{3465}\)
Vậy \(\frac{58}{63}\)> \(\frac{36}{55}\)
a) Ta có: \(\frac{179}{197}< 1\)và \(\frac{971}{917}>1\)
\(\Rightarrow\frac{179}{197}< 1< \frac{971}{917}\)
\(\Rightarrow\frac{179}{197}< \frac{971}{917}\)
b)Ta có: \(\frac{64}{85}< \frac{64}{81}\) mà \(\frac{73}{81}>\frac{64}{81}\)
\(\Rightarrow\frac{64}{85}< \frac{64}{81}< \frac{73}{81}\)
\(\Rightarrow\frac{64}{85}< \frac{73}{81}\)
Tự làm tiếp nha ~
a) Vì 179/197 < 1 ; 971/917 > 1
=> 179/197 < 971/917
b) Vì 64/85 < 64/81 < 73/81
=> 64/85 < 73/81
c) Ta có: 456/461 = 1 - 5/461 ; 123/128 = 1 - 5/128
Vì 5/461 < 5/128 => 1 - 5/461 > 1 - 5/128
=> 456/461 > 123/128
d) 53/57 = 530/570
Áp dụng a/b < 1 => a/b < a+m/b+m (a,b,m thuộc N*)
Do 530/570 < 1 => 530/570 < 530+1/570+1
=> 53/57 < 531/571
e) Ta có: 58/89 > 58/87 = 2/3
36/53 < 36/54 = 2/3
=> 58/89 > 36/53
g) Ta có: 11/32 > 11/33 = 1/3
16/49 < 16/48 = 1/3
=> 11/32 > 16/49
\(\frac{12}{47}>\frac{12}{48}=\frac{1}{4}\)
\(\frac{19}{77}< \frac{19}{76}=\frac{1}{4}\)
\(\Rightarrow\frac{12}{47}>\frac{19}{77}\)
\(\frac{58}{89}< \frac{58}{87}=\frac{2}{3}\)
\(\frac{36}{53}>\frac{36}{54}=\frac{2}{3}\)
\(\Rightarrow\frac{58}{89}< \frac{36}{53}\)