Câu hỏi của Tô Thị Nguyệt Hà

Question

($\dfrac{1}{5}-\dfrac{1}{6}-\dfrac{1}{30}$ ).($\dfrac{21}{22}+\dfrac{22}{23}+......+\dfrac{102}{103}$)

Cô Bé Yêu Đời · Accepted Answer

$\left(\dfrac{1}{5}-\dfrac{1}{6}-\dfrac{1}{30}\right).\left(\dfrac{21}{22}+\dfrac{22}{23}+...+\dfrac{102}{103}\right)$

$=0.\left(\dfrac{21}{22}+\dfrac{22}{23}+...+\dfrac{102}{103}\right)$

$=0$Câu trả lời: $\left(\dfrac{1}{5}-\dfrac{1}{6}-\dfrac{1}{30}\right).\left(\dfrac{21}{22}+\dfrac{22}{23}+...+\dfrac{102}{103}\right)$

$=0.\left(\dfrac{21}{22}+\dfrac{22}{23}+...+\dfrac{102}{103}\right)$

$=0$

Nguyễn Minh khánh · Answer

vì $\dfrac{1}{5}-\dfrac{1}{6}-\dfrac{1}{30}$=0 nên

(15−16−13015−16−130 ).(2122+2223+......+102103)=0Câu trả lời: vì $\dfrac{1}{5}-\dfrac{1}{6}-\dfrac{1}{30}$=0 nên

(15−16−13015−16−130 ).(2122+2223+......+102103)=0