Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(16y^2-4x^2-12x-9=16y^2-\left(2x-3\right)^2\)
\(=\left(4y-2x+3\right)\left(4y+2x-3\right)\)
4x2 - 12x + 9 =
= ( 2x )2 - 2 . 2x . 3 + 32
= ( 2x - 3 )2
Hok tốt!!!!!!!!!!
a) \(4x^2-8x+4-9\left(x-y\right)^2\)
\(=4\left(x^2-2x+1\right)-9\left(x-y\right)^2\)
\(=\left[2\left(x-1\right)\right]^2-\left[3\left(x-y\right)\right]^2\)
\(=\left(2x-2+3x-3y\right)\left(2x-2-3x+3y\right)\)
\(=\left(5x-3y-2\right)\left(3y-x-2\right)\)
b) \(x^3-4x^2+12x-27\)
\(=\left(x^3-27\right)-\left(4x^2-12x\right)\)
\(=\left(x-3\right)\left(x^2+3x+9\right)-4x\left(x-3\right)\)
\(=\left(x-3\right)\left(x^2-x+9\right)\)
\(x^4+4x^3-2x^2-12x+9\)
\(=x^4+3x^3+x^3+3x^2-5x^2-15x+3x+9\)
\(=x^3\left(x+3\right)+x^2\left(x+3\right)-5x\left(x+3\right)+3\left(x+3\right)\)
\(=\left(x+3\right)\left(x^3+x^2-5x+3\right)\)
\(=\left(x+3\right)\left(x^3+3x^2-2x^2-6x+x+3\right)\)
\(=\left(x+3\right)\left[x^2\left(x+3\right)-2x\left(x+3\right)+\left(x+3\right)\right]\)
\(=\left(x+3\right)\left(x+3\right)\left(x^2-2x+1\right)\)
\(=\left(x+3\right)^2\left(x-1\right)^2\)
x3-12x-4x2+27
=(x3+27)-(12x+4x2)
=(x+3)(x2-3x+9)-4x(x+3)
=(x+3)(x2-3x+9-4x)
=(x+3)(x2-7x+9)
\(x^3-12x-4x^2+27\)
\(=x^3+3x^2-7x^2-21x+9x+27\)
\(=x^2\left(x+3\right)-7x\left(x+3\right)+9\left(x+3\right)\)
\(=\left(x+3\right)\left(x^2-7x+9\right)\)
a) \(4x^2-12x+9=\left(2x\right)^2-2\cdot2x\cdot3+3^2=\left(2x-3\right)^2\)
b) \(4x^2+4x+1=\left(2x\right)^2+2\cdot2x\cdot1+1^2=\left(2x+1\right)^2\)
c) \(1+12x+36x^2=1^2+2\cdot1\cdot6x+\left(6x\right)^2=\left(1+6x\right)^2\)
d) \(9x^2-24xy+16y^2=\left(3x\right)^2-2\cdot3x\cdot4y+\left(4y\right)^2=\left(3x-4y\right)^2\)
e) \(8x^3+1=\left(2x\right)^3+1^3=\left(2x+1\right)\left(4x^2+2x+1\right)\)
f) \(-8x^3+27=3^3-\left(2x\right)^3=\left(3-2x\right)\left(9+6x+4x^2\right)\)
=(4x2-12x+9)=[(2x)2-2.2x.3+32]=-(2x-3)2