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Bài 1:
1) Ta có: \(\left(-12\right)+6\cdot\left(-3\right)\)
\(=-12-18\)
=-30
2) Ta có: \(\left(36-2020\right)+\left(2019-136\right)-27\)
\(=36-2020+2019-136-27\)
\(=1-100-27\)
\(=-126\)
3) Ta có: \(\left(144-97\right)-\left(244-197\right)\)
\(=144-97-244+197\)
\(=-100+100=0\)
4) Ta có: \(\left(-24\right)\cdot13-24\cdot\left(-3\right)\)
\(=-24\cdot13+24\cdot3\)
\(=24\cdot\left(-13+3\right)\)
\(=24\cdot\left(-10\right)=-240\)
5) Ta có: \(54+55+56+57+58-\left(64+65+66+67+68\right)\)
\(=54+55+56+57+58-64-65-66-67-68\)
\(=\left(54-64\right)+\left(55-65\right)+\left(56-66\right)+\left(57-67\right)+\left(58-68\right)\)
\(=\left(-10\right)+\left(-10\right)+\left(-10\right)+\left(-10\right)+\left(-10\right)\)
=-50
6) Ta có: \(24\cdot\left(16-5\right)-16\cdot\left(24-5\right)\)
\(=24\cdot16-24\cdot5-16\cdot24+16\cdot5\)
\(=-24\cdot5+16\cdot5\)
\(=5\cdot\left(-24+16\right)\)
\(=-5\cdot8=-40\)
7) Ta có: \(47\cdot\left(23+50\right)-23\cdot\left(47+50\right)\)
\(=47\cdot23+47\cdot50-23\cdot47-23\cdot50\)
\(=47\cdot50-23\cdot50\)
\(=50\cdot\left(47-23\right)\)
\(=50\cdot24=1200\)
8) Ta có: \(\left(-31\right)\cdot47+\left(-31\right)\cdot52+\left(-31\right)\)
\(=-31\cdot\left(47+52+1\right)\)
\(=-31\cdot100=-3100\)
Bài 2:
1) Ta có: \(-17-\left(2x-5\right)=-6\)
\(\Leftrightarrow-17-2x+5+6=0\)
\(\Leftrightarrow-2x-6=0\)
\(\Leftrightarrow-2x=6\)
hay x=-3
Vậy: x=-3
2) Ta có: \(10-2\left(4-3x\right)=-4\)
\(\Leftrightarrow10-8+6x+4=0\)
\(\Leftrightarrow6x+6=0\)
\(\Leftrightarrow6x=-6\)
hay x=-1
Vậy: x=-1
3) Ta có: \(-12+3\left(-x+7\right)=-18\)
\(\Leftrightarrow-12-3x+21+18=0\)
\(\Leftrightarrow-3x+27=0\)
\(\Leftrightarrow-3x=-27\)
hay x=9
Vậy: x=9
4) Ta có: \(-45:\left[5\cdot\left(-3-2x\right)\right]=3\)
\(\Leftrightarrow5\cdot\left(-3-2x\right)=-15\)
\(\Leftrightarrow-2x-3=-3\)
\(\Leftrightarrow-2x=0\)
hay x=0
Vậy: x=0
5) Ta có: x(x+3)=0
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x+3=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-3\end{matrix}\right.\)
Vậy: \(x\in\left\{0;-3\right\}\)
6) Ta có: (x-2)(x+4)=0
\(\Leftrightarrow\left[{}\begin{matrix}x-2=0\\x+4=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-4\end{matrix}\right.\)
Vậy: \(x\in\left\{2;-4\right\}\)
7) Ta có: \(x\left(x+1\right)\left(x-3\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x+1=0\\x-3=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-1\\x=3\end{matrix}\right.\)
Vậy: \(x\in\left\{0;-1;3\right\}\)
Bài 1:
1) Ta có: (−12)+6⋅(−3)(−12)+6⋅(−3)
=−12−18=−12−18
=-30
2) Ta có: (36−2020)+(2019−136)−27(36−2020)+(2019−136)−27
=36−2020+2019−136−27=36−2020+2019−136−27
=1−100−27=1−100−27
=−126
Tớ chcs cậu học thật giỏi nha !
a) [ 316 – ( 25 . 4 + 16 )] : 8 – 24
=( 316 – 116 ) : 8 – 24 = 200 ∶ 8 – 24 = 25 – 24 = 1
b) | -15| + (-27) + 8 + | - 23|
= 15 – 27 + 8 + 23 = 19
c) 5 8 : 5 6 + 2 2 . 3 3 - 2010 0 = 5 2 + 4 . 27 – 1 = 25 + 108 – 1 = 132
35.18-5.7.28
=35.18-35.28
=35.(18-28)
=35.(-10) =-350
Bài 2:
a. $=58(75+50-25)=58.100=5800$
b. $=27.8+4.9-5=216+36-5=247$
Bài 3:
a.
$(x-38):16=12$
$x-38=16\times 12=192$
$x=192+38 = 230$
b.
$10+2x=4^5:4^3=4^2=16$
$2x=16-10=6$
$x=6:2=3$
c.
$440+2(125-x)=546$
$2(125-x)=546-440=106$
$125-x=106:2=53$
$x=125-53=72$
d.
$(x-15):5+20=22$
$(x-15):5=22-20=2$
$x-15=2\times 5=10$
$x=10+15=25$
e.
$2x-138=2^3.3^2=8.9=72$
$2x=72+138 = 210$
$x=210:2=105$
Áp dụng quy tắc dấu ngoặc rồi thực hiện các phép tính, ta thu được kết quả.
a) x + 71. b) 3 - x. c) x + 23. d) 23 - x
a, 3.7.23 - 21.(-17)
= 21.23 + 21.17
= 21.(23 + 17)
= 21.40
= 840
b, 7.6.3 - 7.[(-34) + 18)]
= 7.18 - 7.18 + 34.7
= 34.7
= 238
c, 71.64 + 32.(-7) - 13.32
= 71. 32 . 2 - 7.32 - 32. 13
= 32.(71.2 - 7 - 13)
= 32. (142 - 20)
= 32.122
= 3904
d, 13.(23 - 17) - 13.(23 + 17)
= 13.23 - 13.17 - 13.23 - 13.17
= (13.23 - 13.23) - (13.17 + 13.17)
= - 2.13.17
= - 26.17
= -442
a/57x23+23x44-23
57x23+23x44-23x1
=23x(57+44-1)
=23x100
=2300
b
a) 57 . 23 + 23 . 44 - 23
= 57 . 23 + 23 . 44 - 23 . 1
= ( 57 + 44 - 1 ) . 23
= 100 . 23
= 2300
b) 1672 - [ 49 + ( 13 - 7 )3 ]
= 1672 - [ 49 + 63 ]
= 1672 - [ 49 + 216 ]
= 1672 - 265
= 1407
c) 50 : { 2 . [ 52 - ( 3 . 5 - 22 . 3 )3 ] }
= 50 : { 2 . [ 52 - ( 3 . 5 - 4 . 3 )3 ] }
= 50 : { 2 . [ 52 - ( 3 . 1 )3 ] }
= 50 : { 2 . [ 52 - 27 ] }
= 50 : { 2 . 25 }
= 50 : 50
= 1
d) -2014 + (-999) + 14 + (-2001)
= ( -2014 + 14 ) + [ (-999) + (-2001) ]
= (-2000) + (-3000)
= -5000
Học tốt nhé bạn !
\(D=316-\left(52\cdot23+24\right):23-3\cdot23\)
\(D=316-\left(1196+24\right):23-69\)
\(D=247-1220:23\)
\(D=247-\dfrac{1220}{23}\)
\(D=\dfrac{4461}{23}\)
D=316-1220\23-69
D=6048\23-69
D=4461\23