Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a) \(\frac{x+3}{x+7}=\frac{96}{108}\)
\(\frac{x+3}{x+7}=\frac{8}{9}\)
\(8\left(x+7\right)=9\left(x+3\right)\)
\(8x+56=9x+27\)
\(9x-8x=56-27\)
\(x=29\)
b) \(\frac{4x+...}{-18}=-\frac{1}{6}\)(ĐỀ HÌNH NHƯ BỊ THIẾU)
\(6\left(4x+...\right)=\left(-1\right)\left(-18\right)\)
\(6\left(4x+...\right)=18\)
\(4x+...=18:6\)
\(4x+...=3\)
Bạn từ điền tiếp phần bị thiếu nhé
c) \(\frac{6}{3y-1}=\frac{33}{11}\)
\(\frac{6}{3y-1}=3\)
\(3y-1=\frac{6}{3}\)
\(3y-1=2\)
\(3y=2+1\)
\(3y=3\)
\(y=\frac{3}{3}=1\)
d) \(\frac{5z-3}{3}=\frac{28}{12}\)
\(\frac{5z-3}{3}=\frac{7}{3}\)
\(3\left(5z-3\right)=7.3\)
\(15z-9=21\)
\(15z=21+9\)
\(15z=30\)
\(z=\frac{30}{15}=2\)
rút gọn các phân số sau;
270/450 26/156 123123/237237
4116-14/10290-35 3*3+3*7/6*5+9 6*9-2*17/63*3-119
\(\frac{270}{450}=\frac{270:90}{450:90}=\frac{3}{5}\)
\(\frac{26}{156}=\frac{26:26}{156:26}=\frac{1}{6}\)
\(\frac{123123}{237237}=\frac{123123:3003}{237237:3003}=\frac{41}{79}\)
Tính :
a) 65 / 91 + -33 / 55
\(=\frac{5}{7}-\frac{3}{5}=\frac{4}{35}\)
b) 36 / -84 + 100 // 450
\(=\frac{-3}{7}+\frac{2}{9}=-\frac{13}{63}\)
c) -650 / 1430 + 588 / 686
\(=\frac{5}{11}+\frac{6}{7}=\frac{101}{77}\)
d) 2004 / 2010 + 8 / -670
=\(=\frac{334}{335}-\frac{4}{335}=\frac{66}{67}\)
Rút gọn phân số: \(\dfrac{-270}{450}\);\(\dfrac{11}{-143}\);\(\dfrac{32}{12}\);\(\dfrac{-26}{-156}\)
\(\dfrac{-270}{450}=\dfrac{-9}{15}\)
\(\dfrac{11}{-143}=\dfrac{1}{-13}\)
\(\dfrac{32}{12}=\dfrac{8}{3}\)
\(\dfrac{-26}{-156}=\dfrac{1}{6}\)
65/91 + -33/55=4/35
36/-84 + 100/450=-13/63
-650/1430 + 588/686=31/77
20004/2010 + 8/-670=666/67
a: \(=3\cdot\left(\dfrac{1}{4}-\dfrac{6}{7}+\dfrac{8}{21}\right)\)
\(=3\cdot\left(\dfrac{21}{84}-\dfrac{72}{84}+\dfrac{32}{84}\right)\)
\(=\dfrac{-19}{28}\)
b: \(=\dfrac{-2}{3}\left(\dfrac{1}{9}-\dfrac{1}{6}-\dfrac{1}{11}\right)\)
\(=\dfrac{-2}{3}\cdot\dfrac{-29}{198}=\dfrac{29}{99\cdot3}=\dfrac{29}{297}\)
c: \(=\dfrac{-3}{7}+\dfrac{4}{25}+\dfrac{5}{16}+\dfrac{3}{16}\)
\(=\dfrac{-75+28}{175}+\dfrac{1}{2}\)
\(=\dfrac{-47}{175}+\dfrac{1}{2}=\dfrac{-94+175}{350}=\dfrac{81}{350}\)
d: \(=\dfrac{-4}{9}\cdot\left(\dfrac{1}{26}-\dfrac{1}{2}-\dfrac{1}{8}\right)\)
\(=\dfrac{-4}{9}\cdot\dfrac{-61}{104}=\dfrac{61}{26\cdot9}=\dfrac{61}{234}\)
a) \(\frac{270}{-450}+\frac{4545}{5454}=-\frac{3}{5}+\frac{5}{6}=\frac{7}{30}\)
b) \(\frac{-33}{429}+\frac{-156}{-26}+\frac{224}{-84}=\frac{-1}{13}+6+\frac{-56}{21}=\frac{127}{39}\)
c) \(\frac{405}{-567}+\frac{-161}{552}+\frac{162}{-243}=-\frac{5}{7}+\frac{-7}{24}+\frac{-2}{3}=\frac{-281}{168}\)
d) \(-\frac{2}{3}\left(\frac{2}{18}+\frac{-6}{12}-\frac{3}{33}\right)=-\frac{2}{3}\left(\frac{1}{9}+\frac{-1}{2}-\frac{1}{11}\right)\)
\(=-\frac{2}{3}.\left(-\frac{95}{198}\right)=\frac{95}{297}\)