Câu hỏi của Minh Lương

Question

Chứng tỏ rằng 1/101+1/102+1/103+...+1/200>1/2

bảo nam trần · Accepted Answer

Ta có: $\dfrac{1}{101}>\dfrac{1}{200};\dfrac{1}{102}>\dfrac{1}{200};....;\dfrac{1}{199}>\dfrac{1}{200}$

$\Rightarrow\dfrac{1}{101}+\dfrac{1}{102}+...+\dfrac{1}{200}>\dfrac{1}{200}+\dfrac{1}{200}+...+\dfrac{1}{200}=\dfrac{100}{200}=\dfrac{1}{2}$

Vậy...Câu trả lời: Ta có: $\dfrac{1}{101}>\dfrac{1}{200};\dfrac{1}{102}>\dfrac{1}{200};....;\dfrac{1}{199}>\dfrac{1}{200}$

$\Rightarrow\dfrac{1}{101}+\dfrac{1}{102}+...+\dfrac{1}{200}>\dfrac{1}{200}+\dfrac{1}{200}+...+\dfrac{1}{200}=\dfrac{100}{200}=\dfrac{1}{2}$

Vậy...

Fa Châu · Answer

bCâu trả lời: b