Chứng minh rằng với mọi số nguyên dương k" role="presentation" style="border:0px; direction:ltr; display:inline-block; float:none; font-size:16.38px; line-height:0; margin:0px; max-height:none; max-width:none; min-height:0px; min-width:0px; padding:1px 0px; position:relative; white-space:nowrap; word-spacing:normal; word-wrap:normal" class="MathJax_CHTML mjx-chtml">k ; ta có đẳng thức :
1sin2⁡π4k+2+1sin2⁡3π4k+2+1sin2⁡5π4k+2+⋯+1sin2⁡(2k−1)π4k+2=2k(k+1)" role="presentation" style="border:0px; direction:ltr; display:inline-table; float:none; font-size:16.38px; line-height:0; margin:0px; max-height:none; max-width:none; min-height:0px; min-width:0px; padding:1px 0px; position:relative; text-align:left; word-spacing:normal; word-wrap:normal" class="MathJax_CHTML mjx-chtml">1sin2π4k+2+1sin23π4k+2+1sin25π4k+2+⋯+1sin2(2k−1)π4k+2=2k(k+1