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10 tháng 12 2021

Chia nhỏ ra ik ạ

10 tháng 12 2021

\(\left(2x+3\right)\left(2x-3\right)-4x\left(x+5\right)=4x^2-9-4x^2-20x=-20x-9\)

\(5x\left(x-3\right)+\left(x-2\right)^2=5x^2-15x+x^2-4x+4=6x^2-19x+4\)

\(x\left(x+2\right)-\left(x-3\right)\left(x+3\right)=x^2+2x-\left(x^2-9\right)=x^2+2x-x^2+9=2x+9\)

 

4 tháng 8 2019

\(\frac{3}{x+1}+\frac{2}{x+2}=\frac{5x+4}{x^2+3x+2}.\)ĐKXĐ: \(x\ne-1;-2\)

\(\Leftrightarrow\frac{3\left(x+2\right)}{\left(x+1\right)\left(x+2\right)}+\frac{2\left(x+1\right)}{\left(x+1\right)\left(x+2\right)}=\frac{5x+4}{\left(x+1\right)\left(x+2\right)}\)

\(\Leftrightarrow3x+6+2x+2=5x+4\)

\(\Leftrightarrow3x+2x-5x=-6-2+4\)

\(\Leftrightarrow0x=-4\)

=> PT vô nghiệm 

\(2;\frac{2}{3x-1}-\frac{15}{6x^2-x-1}=\frac{3}{2x-1}\)

\(\Leftrightarrow\frac{2\left(2x-1\right)}{\left(2x-1\right)\left(3x-1\right)}-\frac{15}{6x^2+3x-2x-1}=\frac{3\left(3x-1\right)}{\left(2x-1\right)\left(3x-1\right)}\)

\(\Leftrightarrow\frac{4x-2-15}{\left(2x-1\right)\left(3x-1\right)}=\frac{9x-3}{\left(2x-1\right)\left(3x-1\right)}\)

\(\Leftrightarrow4x-2-15=9x-3\)

\(\Leftrightarrow4x-9x=2+15-3\)

\(\Leftrightarrow-5x=14\)

.....

4 tháng 8 2019

mấy cái này mẫu nào dài cậu phân tích ra : 

VD : câu  3 : \(3x^2-4x+1\)

\(=3x^2-3x-x+1\)

\(=3x\left(x-1\right)-\left(x-1\right)\)

\(=\left(3x-1\right)\left(x-1\right)\)

r bắt đầu giải PHương trình :)) Mấy câu còn lại tương tự 

6 tháng 9 2020

1. (x + 2)(x2 - 2x + 4) - (x3 + 2x2) = 5

=> x(x2 - 2x + 4) + 2(x2 - 2x + 4) - x3 - 2x2 - 5 = 0

=> x3 - 2x2 + 4x + 2x2 - 4x + 8 - x3 - 2x2 - 5 = 0

=> (x3 - x3) + (-2x2 + 2x2 - 2x2) + (4x - 4x) + (8 - 5) = 0

=> -2x2 + 3 = 0

=> -2x2 = -3

=> x2 = 3/2

=> x = \(\pm\sqrt{\frac{3}{2}}\)

2. \(\left(x+5\right)^2-6=0\)

=> x2 + 10x + 25 - 6 = 0

=> x2 + 10x + 19 = 0

=> x vô nghiệm(do mình không để căn nên ghi vô nghiệm thôi nhá)

3. \(\left(x+3\right)\left(x^2-3x+9\right)-x^3=2x\)

=> x(x2 - 3x + 9) + 3(x2 - 3x + 9) - x3 - 2x = 0

=> x3 - 3x2 + 9x + 3x2 - 9x + 27 - x3 - 2x = 0

=> (x3 - x3) + (-3x2 + 3x2) + (9x - 9x - 2x) + 27 = 0

=> -2x + 27 = 0

=> -2x = -27

=> x = 27/2

4. \(\left(x-2\right)^3-x^3+6x^2=7\)

=> x3 - 6x + 12x - 8 - x3 + 6x2 = 7

=> (x3 - x3) + (-6x2 + 6x2) + 12x - 8 = 7

=> 12x - 8 = 7

=> 12x = 15

=> x = 5/4

5. \(3\left(x-2\right)^2+9\left(x-1\right)-3\left(x^2+x-3\right)=12\)

=> 3x2 - 12x + 12 + 9x - 9 - 3x2 - 3x + 9 = 12

=> (3x2 - 3x2) + (-12x + 9x - 3x) + (12 - 9 + 9) = 12

=> -6x + 12 = 12

=> -6x = 0

=> x = 0

6. \(\left(4x+3\right)^2-\left(4x-3\right)^2-5x-2=0\)

=> 48x - 5x - 2 = 0

=> 43x - 2 = 0

=> 43x = 2

=> x = 2/43

Còn bài cuối tự làm :>

6 tháng 9 2020

Anh Sang làm cầu kì quá ;-;

1. ( x + 2 )( x2 - 2x + 4 ) - ( x3 + 2x2 ) = 5

<=> x3 + 8 - x3 - 2x2 = 5

<=> 8 - 2x2 = 5

<=> 2x2 = 3

<=> x2 = 3/2

<=> \(x^2=\left(\pm\sqrt{\frac{3}{2}}\right)^2\)

<=> \(x=\pm\sqrt{\frac{3}{2}}\)

2. ( x + 5 )2 - 6 = 0

<=> ( x + 5 )2 - ( √6 )2 = 0

<=> ( x + 5 - √6 )( x + 5 + √6 ) = 0

<=> \(\orbr{\begin{cases}x+5-\sqrt{6}=0\\x+5+\sqrt{6}=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=\sqrt{6}-5\\x=-\sqrt{6}-5\end{cases}}\)

3. ( x + 3 )( x2 - 3x + 9 ) - x3 = 2x

<=> x3 + 27 - x3 = 2x

<=> 27 = 2x

<=> x = 27/2

4. ( x - 2 )3 - x3 + 6x2 = 7

<=> x3 - 6x2 + 12x - 8 - x3 + 6x2 = 7

<=> 12x - 8 = 7

<=> 12x = 15

<=> x = 15/12 = 5/4

5. 3( x - 2 )2 + 9( x - 1 ) - 3( x2 + x - 3 ) = 12

<=> 3( x2 - 4x + 4 ) + 9x - 9 - 3x2 - 3x + 9 = 12

<=> 3x2 - 12x + 12 + 6x - 3x2 = 12

<=> -6x + 12 = 12

<=> -6x = 0

<=> x = 0

6. ( 4x + 3 )2 - ( 4x - 3 )2 - 5x - 2 = 0

<=> 16x2 + 24x + 9 - ( 16x2 - 24x + 9 ) - 5x - 2 = 0

<=> 16x2 + 24x + 9 - 16x2 + 24x - 9 - 5x - 2 = 0

<=> 43x - 2 = 0

<=> 43x = 2

<=> x = 2/43

7, ( 4x + 7 )( 2 - 3x ) - ( 6x + 2 )( 5 - 2x ) = 0

<=> -12x2 - 13x + 14 - ( -12x2 + 26x + 10 ) = 0

<=> -12x2 - 13x + 14 + 12x2 - 26x - 10 = 0

<=> -39x + 4 = 0

<=> -39x = -4

<=> x = 4/39

5 tháng 7 2018

1) a) \(\left(3x-1\right)\left(9x^2+3x+1\right)-4x\left(x-5\right)\)

\(=27x^3+9x^2+3x-9x^2-3x-1-4x^2+20x\)

\(=27x^3+\left(9x^2-9x^2-4x^2\right)+\left(3x-3x+20x\right)+\left(-1\right)\)

\(=27x^3-4x^2+20x-1\)

b)\(\left(7x+2\right)\left(3-4x\right)-\left(x+3\right)\left(x^2-3x+9\right)\)

\(=21x-28x^2+6-8x-x^3+3x^2-9x-3x^2+9x-27\)

\(=\left(21x-8x-9x+9x\right)+\left(-28x^2+3x^2-3x^2\right)\)\(+\left(6-27\right)\)\(+\left(-x^3\right)\)

\(=13x-28x^2-21-x^3\)

c)\(\left(4x+3\right)\left(4x-3\right)-\left(2-x\right)\left(4+2x+x^2\right)\)

\(=16x^2-12x+12x-9-8-4x-2x^2+4x+2x^2+x^3\)

\(=\left(16x^2-2x^2+2x^2\right)+\left(-12x+12x-4x+4x\right)\)\(+\left(-9-8\right)\)\(+x^3\)

\(=16x^2-17+x^3\)

d)\(\left(3x-8\right)\left(-5x+6\right)-\left(4x+1\right)\left(3x-2\right)\)

\(=-15x^2+18x+40x-48-12x^2+8x-3x+2\)

\(=\left(-15x^2-12x^2\right)+\left(18x+40x+8x-3x\right)\)\(+\left(-48+2\right)\)

\(=-27x^2+63x-46\)

e)\(\left(3x-6\right)4x-2x\left(3x+5\right)-4x^2\)

\(=12x^2-24x-6x^2-10x-4x^2\)

\(=\left(12x^2-6x^2-4x^2\right)+\left(-24x-10x\right)\)

\(=2x^2-34x\)

f)\(\left(5x-6\right)\left(6x-5\right)-x\left(3x+10\right)\)

\(=30x^2-25x-36x+30-3x^2-10x\)

\(=\left(30x^2-3x^2\right)+\left(-25x-36x-10x\right)+30\)

\(=27x^2-71x+30\)

5 tháng 7 2018

2) a)\(x\left(x+3\right)-x^2=6\)

\(\Rightarrow x^2+3x-x^2=6\)

\(\Rightarrow\left(x^2-x^2\right)+3x=6\)

\(\Rightarrow3x=6\)

\(\Rightarrow x=2\)

Vậy x=2

b) \(2x\left(x-5\right)+x\left(-2x-1\right)=6\)

\(\Rightarrow2x^2-10x-2x^2-x=6\)

\(\Rightarrow\left(2x^2-2x^2\right)+\left(-10x-x\right)=6\)

\(\Rightarrow-11x=6\)

\(\Rightarrow x=-\dfrac{6}{11}\)

\(\)Vậy \(x=-\dfrac{6}{11}\)

c) x(x+5)-(x+1)(x-2)=7

\(\Rightarrow x^2+5x-x^2+2x-x+2=7\)

\(\Rightarrow\left(x^2-x^2\right)+\left(5x+2x-x\right)=7-2\)

\(\Rightarrow6x=5\)

\(\Rightarrow x=\dfrac{5}{6}\)

Vậy x=\(\dfrac{5}{6}\)

d)\(\left(3x+4\right)\left(6x-3\right)-\left(2x+1\right)\left(9x-2\right)=10\)

\(\Rightarrow18x^2-9x+24x-12-18x^2+4x-9x+2=10\)

\(\Rightarrow\left(18x^2-18x^2\right)+\left(-9x+24x+4x-9x\right)+\left(-12+2\right)=10\)

\(\Rightarrow10x-10=10\)

\(\Rightarrow10x=20\)

\(\Rightarrow x=2\)

Vậy x=2

26 tháng 12 2018

1) 4x\(^2\).(5x3+2x-1)

= 20x\(^5\)+8x\(^3\)-4x\(^2\).

2) 4x\(^3\): x2

= 4x

3) ( 15x2y3-10x3y3+6xy): 5xy

= 3xy2-2x2y2+\(\dfrac{6}{5}\)

4) (5x3+14x2+12x+8 ): (x+2)

= 5x2+4x+4

5)\(\dfrac{7}{2x}\)+\(\dfrac{11}{3y^2}\)

=\(\dfrac{7.3y^2+11.2x}{6xy^2}\) =\(\dfrac{21y^2+22x}{6xy^2}\) = \(\dfrac{21+22}{6}\) =\(\dfrac{43}{6}\)

6) \(\dfrac{x}{x+2}\) +\(\dfrac{3}{\left(x+2\right)\left(4x-7\right)}\)

7)\(\dfrac{3}{x-y}\)-\(\dfrac{2x^2}{x+y}\)

= \(\dfrac{3\left(x+y\right)-2\left(x+y\right)}{\left(x-y\right)\left(x+y\right)}\)=\(\dfrac{3x+3y-2x-2y}{\left(x-y\right)\left(x+y\right)}\)=\(\dfrac{x+y}{\left(x-y\right)\left(x+y\right)}\)=\(\dfrac{1}{x-y}\).

8)\(\dfrac{1}{2}\)x2y2.(2x+y)(2x-y)

= \(\dfrac{1}{2}\)x2y2.(4x2-2xy+2xy-y2)

= \(\dfrac{1}{2}\)x2y2.(4x2-y2)

= 2x4y2-\(\dfrac{1}{2}\)x2y4

9) (x-\(\dfrac{1}{2}\)).(x+\(\dfrac{1}{2}\)).(4x-1)

= x2.(4x-1)

= 4x3-x2

10)\(\dfrac{3x}{2x+6}\)+\(\dfrac{6-x}{2x^2+6x}\)

= \(\dfrac{3x}{2\left(x+3\right)}\)+\(\dfrac{6-x}{2x\left(x+3\right)}\)= \(\dfrac{3x^2+6-x}{2x\left(x+3\right)}\)=\(\dfrac{3-x}{3}\)= -x

11) x2-\(\dfrac{1}{2x-2}\)+3x+\(\dfrac{3}{1-x^2}\)

12)\(\dfrac{x^2}{x^2-y^2}\)-\(\dfrac{x-y}{x^2-y^2}\)

= \(\dfrac{x^2-xy}{\left(x-y\right)\left(x+y\right)}\)=\(\dfrac{x\left(x-y\right)}{\left(x-y\right)\left(x+y\right)}\)= \(\dfrac{x}{x+y}\)

26 tháng 12 2018

cảm ơn bạn nhé ^^

1,(2x + 3 ) \(^{^{ }2}\)=\(\left(2x\right)^2+2.2x.3+3^2\)

=\(4x^2+12x+9\)

2, ( 3x + 2y )\(^2=\left(3x\right)^2+2.3x.2y+\left(2y\right)^2\)

=\(9x^2+12xy+4y^2\)

3,(3a -1 )\(^2=\left(3a\right)^2-2.3a.1+1^2\)

\(=9a^2-6a+1\)

4, (a - 2 )\(^2=a^2-2.a.2+2^2\)

=\(a^2-4a+4\)

5, ( 1 - 5a )\(^2=1^2-2.1.5a+\left(5a\right)^2\)

=\(1-10a+25a\)

6, ( x - 4 )\(^3=x^3-3x^24+3x4^2-4^3\)

=\(x^3-12x^2+48x-64\)

23 tháng 3 2020

cái này có vội không? nếu không thì sáng mai mình giải cho bạn?

23 tháng 3 2020

Hoàng Ngọc Anh: chắc không cần đâu bạn, có thằng kia nhờ mình đăng hộ ý mà! Mà bạn cũng trả lời câu hỏi này rồi đó! :)

18 tháng 7 2017

a) \(\left(4x-1\right)^2-\left(3x+2\right)\left(3x-2\right)=\left(7x-1\right)\left(x+2\right)+\left(2x+1\right)^2-\left(4x^2+7\right)\)(1)

\(\Leftrightarrow\left(16x^2-8x+1\right)-\left(9x^2-4\right)=\left(7x^2+14x-x-2\right)+\left(4x^2+4x+1\right)-\left(4x^2+7\right)\)

\(\Leftrightarrow16x^2-8x+1-9x^2+4=7x^2+13x-2+4x^2+4x+1-4x^2-7\)

\(\Leftrightarrow7x^2-8x+5=7x^2+17x-8\)

\(\Leftrightarrow7x^2-8x-7x^2-17x=-8-5\)

\(\Leftrightarrow-25x=-13\)

\(\Leftrightarrow x=\dfrac{13}{25}\)

Vậy tập nghiệm phương trình (1) là \(S=\left\{\dfrac{13}{25}\right\}\)

18 tháng 7 2017

gắp cái gì

28 tháng 7 2018

\(a.4\left(x+2\right)-7\left(2x-1\right)+9\left(3x-4\right)=30\\ 4x+8-14x+7+27x-36=30\\ 17x+15=66\\ 17x=51\Rightarrow x=3\)

\(b.2\left(5x-8\right)-3\left(4x-5\right)=4\left(3x-4\right)+11\\ =10x-16-12x+15=12x-16+11\\ -2x-1=12x-5\\ \Leftrightarrow-2x-12x=1-5\\ \Leftrightarrow-14x=-4\\ \Leftrightarrow x=\dfrac{7}{2}\)

\(c.4x^2+3\left(2x^2+1\right)=2x\left(5x-7\right)\\ 4x^2+6x^2+3=10x^2-14x\\ 10x^2+3=10x^2-14x\\ \Leftrightarrow3=14x\\\Rightarrow x=\dfrac{3}{14}\)

\(d.x\left(x^2-7\right)=2x\left(\dfrac{1}{2}x^2+6\right)+8\\ x^3-7x=x^3+12x+8\\ \Leftrightarrow-7x=12x+8\\ \Leftrightarrow-7x-12x=8\\ \Leftrightarrow-19x=8\Rightarrow x=-\dfrac{8}{19}\)