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a) Ta có: \(\left(2^2\right)^3\cdot4^5\)
\(=2^6\cdot2^{10}\)
\(=2^{16}=65536\)
b) Ta có: \(\left[\left(-4\right)^2\right]^2\cdot6\)
\(=16^2\cdot6\)
\(=256\cdot6=1536\)
c) Ta có: \(\frac{16}{25}\cdot\left(\frac{4}{5}\right)^3\)
\(=\left(\frac{4}{5}\right)^2\cdot\left(\frac{4}{5}\right)^3\)
\(=\left(\frac{4}{5}\right)^5\)
\(=\frac{1024}{3125}\)
d) Ta có: \(\left(\frac{121}{64}\right)^2\cdot\left(-\frac{64}{11}\right)^2\)
\(=\frac{121^2}{64^2}\cdot\frac{64^2}{11^2}\)
\(=11^2=121\)
e) Ta có: \(\left[\left(-3\right)^3\right]^3\cdot271:125\)
\(=\left(-27\right)^3\cdot\frac{271}{125}\)
\(=\frac{-5334093}{125}\)
\(\left(3x-\dfrac{5}{12}\right)^2-\dfrac{121}{64}=0\)
\(\left(3x-\dfrac{5}{12}\right)^2\) \(=0+\dfrac{121}{64}\)
\(3x-\dfrac{5}{12}\) \(=\sqrt{\dfrac{121}{64}}=\dfrac{11}{8}\)
\(3x\) \(=\dfrac{11}{8}+\dfrac{5}{12}=\dfrac{33+10}{24}=\dfrac{43}{24}\)
\(x\) \(\dfrac{3.43}{24}=\dfrac{43}{8}\)
a: \(=\left(\dfrac{11}{17}+\dfrac{6}{17}\right)+\left(-\dfrac{5}{13}-\dfrac{8}{13}\right)+\dfrac{11}{25}\)
=11/25+1-1=11/25
b: \(=\sqrt{36\cdot\dfrac{1}{4}}+11=9+11=20\)
c: \(=\left(0.25\right)^8\cdot4^8=\left(0.25\cdot4\right)^8=1\)
d: \(=2.8\left(-6.5-3.5\right)=-10\cdot2.8=-28\)
Bạn ơi cả 3x-5 chia cho 12 hay chỉ có 5 chia cho 12 thui z ạ
\(\left(3x-\frac{5}{12}\right)^2-\frac{121}{64}=0\)
\(\left(3x-\frac{5}{12}\right)^2=\frac{121}{64}\)
\(3x-\frac{5}{12}=\sqrt{\frac{121}{64}}\)
\(3x-\frac{5}{12}=\frac{11}{8}\)
\(3x=\frac{11}{8}+\frac{5}{12}\)
\(3x=\frac{33}{24}+\frac{10}{24}\)
\(3x=\frac{43}{24}\)
\(x=\frac{43}{24}:3\)
\(x=\frac{43}{24}\cdot\frac{1}{3}\)
\(x=\frac{43}{72}\)
Đáp án B