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20 tháng 6 2015

Nối B với N 

Xét tam giác BNC và NMC 

- Chung chiều cao hạ từ đỉnh N xuống BC

- MC = 3 lần BC

=> SNMC = 3 lần SBNC = 15 X 3 = 45 ( cm2 )

Xét 2 tam giác ABC và BNC

- Chung chiều cao hạ từ đỉnh B xuống cạnh AC 

- NC = 3 lần AC

=> SABC = SBNC X 3 = 45 X 3 = 135 ( CM2 )

                                    Đáp số : 135 cm2

19 tháng 6 2015

Nối B với N 

Xét tam giác BNC và NMC 

- Chung chiều cao hạ từ đỉnh N xuống BC

- MC = 3 lần BC

=> SNMC = 3 lần SBNC = 15 X 3 = 45 ( cm2 )

Xét 2 tam giác ABC và BNC

- Chung chiều cao hạ từ đỉnh B xuống cạnh AC 

- NC = 3 lần AC

=> SABC = SBNC X 3 = 45 X 3 = 135 ( CM2 )

                                    Đáp số : 135 cm2

8 tháng 6 2021

Câu:1 Vì AM=MB , AN=NC 

Nên diện tích tam giác AMN=2ABC

=> Diện tích tam gác AMN = 180:2 = 90

15 tháng 4 2019

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3 tháng 5 2022

Smnc=1/2

Stam giác ABC là

(3×2) ×3 =18cm2

DS 18cm2

3 tháng 5 2022

Tớ lười lắm nên viết tắt nhá

27 tháng 1 2016

SBNC = 1/4SABC  => SABN = 3/4SABC

SNBM = 1/3SABN  = 1/3 x 3/4SABC = 1/4SABC

Suy ra :

SBMNC = SBNC + SNBM = 1/4SABC + 1/4SABC = 1/2SABC

Diện tích hình tam giác ABC là :

120 : 2 = 240 (cm2)

28 tháng 1 2016

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