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ne ban minh biet cau tra loi nhung lam the nao bam ngoac vuong
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a) \(3^{x+1}.15=135\)
\(\Rightarrow3^{x+1}=9\)
\(\Rightarrow3^{x+1}=3^2\)
\(\Rightarrow x+1=2\)
\(\Rightarrow x=1\)
Vậy \(x=1\)
b) \(x+2x+2^2x+....+2^{2016}x=2^{2017}-1\\ \Rightarrow x\left(2+2^2+...+2^{2016}\right)=2^{2017}-1\\ \Rightarrow x\left(2^{2017}-2\right)=2^{2017}-1\)
c) \(x\left(x-1\right)+\left(x-1\right)^2=0\\ \Rightarrow x\left(x-1\right)+\left(x-1\right)\left(x-1\right)=0\\ \Rightarrow\left(x-1\right)\left(x+\left(x-1\right)\right)=0\\ \Rightarrow\left(x-1\right)\left(2x-1\right)=0\\ \Rightarrow\begin{cases}x-1=0\\2x-1=0\end{cases}\)
d) \(2^2.2^5\le2^{x-5}\le2^{10}\\ \Rightarrow2^7\le2^{x-5}\le2^{10}\)
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làm con trai cũng có nhìu cái ko được như con gái đâu kiss_rain_and_you
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a)\(2^3.3^x-23=7^2\\ 2^3.3^x=72\\ 3^x=9\\ \Rightarrow x=2\)
b)\(2^{x+1}.2^{2014}=2^{2015}\\ 2^{x+1}=2^1\\ \Leftrightarrow x+1=1\\ \Rightarrow x=0\)
S=1+32+34+...+32016
\(\Rightarrow\)32S=32+34+...+32017
\(\Rightarrow\)9S-S=(32+34+...+32017)-(1+32+34+...+32016)
\(\Rightarrow\)8S=32017-1
\(\Rightarrow\)8S+1=32017
\(\Rightarrow\)32017=3x
\(\Rightarrow\)x = 2017
ok xong tu lau rồi