Question

[Nguyễn Minh Dương]

Cho hình sau, bt \(\widehat{xOy}=a.\) Tính số đo \(\widehat{OAm}\) để \(Am//Ox\)

Answer 1

[Minh Hiếu]

\(Am//Ox\Rightarrow\widehat{xOy}=\widehat{mAy}=a\)

\(\Rightarrow\widehat{OAm}=180^o-\widehat{mAy}=180^o-a\)

Answer 2

[『Kuroba ム Tsuki Ryoo ︵²ᵏ⁷』]

`#3107`

Ta có:

`\text {AM // Ox}`

`=>` \(\widehat{\text{xOA}}=\widehat{\text{A}_1}\) (2 góc đồng vị)

Mà \(\widehat{\text{A}_1}\) và \(\widehat{\text{OAm}}\) là 2 góc kề bù

`=>`\(\widehat{\text{A}_1}+\widehat{\text{OAm}}=180^0\)

`=>`\(\widehat{\text{xOA}}+\widehat{\text{OAm}}=180^0\)

`=>`\(a+\widehat{\text{ }\text{OAm}}=180^0\)

`=>`\(\widehat{\text{OAm}}=180^0-a\)

Vậy, để `\text {AM // Ox}` thì cần thỏa mãn \(\widehat{\text{OAm}}=180^0-a.\)