Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
;y=-1
; Q(x) = x2 – 9.; R(x) = 3x2 – 4x
)
21:
a: \(f\left(x\right)=4x^4-x^3-4x^2+x-1\)
\(g\left(x\right)=x^4+4x^3+x-5\)
b: f(x)-g(x)
=4x^4-x^3-4x^2+x-1-x^4-4x^3-x+5
=3x^4-5x^3-4x^2+4
f(x)+g(x)
=4x^4-x^3-4x^2+x-1+x^4+4x^3+x-5
=5x^4+3x^3-4x^2+2x-6
c: g(-1)=1-4-1-5=-9
a) Ta có: \(M\left(x\right)=3x^3+x^2+4x^4-x-3x^3+5x^4+2x^2-6\)
\(=\left(4x^4+5x^4\right)+\left(3x^3-3x^3\right)+\left(x^2+2x^2\right)-x-6\)
\(=9x^4+3x^2-x-6\)
Ta có: \(N\left(x\right)=-2x^2-x^4+4x^3-x^2-5x^3+3x+5+x\)
\(=-x^4+\left(4x^3-5x^3\right)+\left(-2x^2-x^2\right)+\left(3x+x\right)+5\)
\(=-x^4-x^3-3x^2+4x+5\)
c) Ta có: M(x)+N(x)
\(=9x^4+3x^2-x-6-x^4-x^3-3x^2+4x+5\)
\(=8x^4-x^3+3x-1\)
a: \(M\left(x\right)=9x^4+2x^2-x-6\)
\(N\left(x\right)=-x^4-x^3-2x^2+4x+1\)
b: \(P\left(x\right)=8x^4-x^3+3x-5\)
\(Q\left(x\right)=10x^4+x^3+4x^2-5x-7\)
a: \(M\left(x\right)=9x^4+2x^2-x-6\)
\(N\left(x\right)=-x^4-x^3-2x^2+4x+1\)
b: \(P\left(x\right)=8x^4-x^3+3x-5\)
\(Q\left(x\right)=10x^4+x^3+4x^2-5x-7\)
a) Thu gọn và sắp xếp:
\(P\left(x\right)=x^2+5x^4-3x^3+x^2+4x^4+3x^3-x+5\)
\(P\left(x\right)=\left(5x^4+4x^4\right)-\left(3x^3-3x^3\right)+\left(x^2+x^2\right)-x+5\)
\(P\left(x\right)=9x^4+2x^2-x+5\)
\(Q\left(x\right)=x-5x^3-x^2-x^4+4x^3-x^2+3x-1\)
\(Q\left(x\right)=x^4-\left(5x^3-4x^3\right)-\left(x^2+x^2\right)+\left(x+3x\right)-1\)
\(Q=x^4-x^3-2x^2+4x-1\)
b) \(P\left(x\right)+Q\left(x\right)\)
\(=\left(9x^4+2x^2-x+5\right)+\left(x^4-x^3-2x^2+4x-1\right)\)
\(=9x^4+2x^2-x+5+x^4-x^3-2x^2+4x-1\)
\(=\left(9x^4+x^4\right)-x^3+\left(2x^2-2x^2\right)-\left(x-4x\right)+\left(5-1\right)\)
\(=10x^4-x^3+3x+4\)
\(P\left(x\right)-Q\left(x\right)\)
\(=\left(9x^4+2x^2-x+5\right)-\left(x^4-x^3-2x^2+4x-1\right)\)
\(=9x^4+2x^2-x+5-x^4+x^3+2x^2-4x+1\)
\(=\left(9x^4-x^4\right)+x^3+\left(2x^2+2x^2\right)-\left(x+4x\right)+\left(5-1\right)\)
\(=8x^4+x^3+4x^2-5x+4\)
A(x) = x2 + 5x4 - 3x3 + x2 - 4x4 + 3x3 - x + 5
= ( 5x4 - 4x4 ) + ( 3x3 - 3x3 ) + ( x2 + x2 ) - x + 5
= x4 + 2x2 - x + 5
B(x) = x - 5x3 - x2 - x4 + 5x3 - x2 - 3x + 1
= -x4 + ( 5x3 - 5x3 ) + ( -x2 - x2 ) + ( -3x + x ) + 1
= -x4 - 2x2 - 2x + 1
M(x) = A(x) + B(x)
= x4 + 2x2 - x + 5 + ( -x4 - 2x2 - 2x + 1 )
= x4 + 2x2 - x + 5 - x4 - 2x2 - 2x + 1
= -3x + 6
N(x) = A(x) - B(x)
= x4 + 2x2 - x + 5 - ( -x4 - 2x2 - 2x + 1 )
= x4 + 2x2 - x + 5 + x4 + 2x2 + 2x - 1
= 2x4 + 4x2 + x + 4
M(x) = 0 <=> -3x + 6 = 0
<=> -3x = -6
<=> x = 2
Vậy nghiệm của M(x) là 2
\(\cdot\) `\text {dnammv}`
`7,`
`a,`
`M(x)=\(-5x^4+3x^5+x\left(x^2+5\right)+14x^4-6x^5-x^3+x-1\)
`M(x)=-5x^4+3x^5+x^3+5x+14x^4-6x^5-x^3+x-1`
`=(3x^5-6x^5)+(-5x^4+14x^4)+(x^3-x^3)+(5x+x)-1`
`=-3x^5+9x^4+6x-1`
`N(x)=x^4(x - 5) - 3x^3 + 3x + 2x^5 - 4x^4 + 3x^3 - 5`
`= x^5-5x^4-3x^3+3x+2x^5-4x^4+3x^3-5`
`= 3x^5-9x^4+3x-5`
`b,`
`H(x)= N(x)+ M(x)`
`-> H(x)=(-3x^5+9x^4+6x-1)+(3x^5-9x^4+3x-5)`
`= -3x^5+9x^4+6x-1+3x^5-9x^4+3x-5`
`= (-3x^5+3x^5)+(9x^4-9x^4)+(6x+3x)+(-1-5)`
`= 9x-6`
`G(x)=M(x)-N(x)`
`-> G(x)= (-3x^5+9x^4+6x-1)-(3x^5-9x^4+3x-5)`
`= -3x^5+9x^4+6x-1-3x^5+9x^4-3x+5`
`= (-3x^5-3x^5)+(9x^4+9x^4)+(6x-3x)+(-1+5)`
`= -6x^5+18x^4+3x+4`
`c,`
`H(x)=9x-6`
Hệ số cao nhất: `9`
Hệ số tự do: `-6`
`G(x)= -6x^5+18x^4+3x+4`
Hệ số cao nhất: `-6`
Hệ số tự do: `4`
`d,`
`H(1)=9*1-6=9-6=3`
`H(-1)=9*(-1)-6=-9-6=-15`
`G(1)=-6*1^5+18*1^4+3*1+4=-6+18+3+4=12+3+4=15+4=19`
`G(0)=-6*0^5+18*0^4+3*0+4=0+0+0+4=4`
`H(x)=9x-6=0`
`-> 9x=0+6`
`-> 9x=6`
`-> x= 6 \div 9`
`-> x=`\(\dfrac{2}{3}\)
Vậy, nghiệm của đa thức là `x=`\(\dfrac{2}{3}\)
a. Ta có:
f(x) = -2x2 - 3x3 - 5x + 5x3 - x + x2 + 4x + 3 + 4x2
= 2x3 + 3x2 - 2x + 3 (0.5 điểm)
g(x) = 2x2 - x3 + 3x + 3x3 + x2 - x - 9x + 2
= 2x3 + 3x2 - 7x + 2 (0.5 điểm)