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\(A=\frac{\left(2018+1\right).2018}{2}=2037171\)
\(B=1.2+2.3+3.4+...+2018.2019\)
\(3B=1.2.3+2.3.3+3.4.3+...+2018.2019.3\)
\(3B=1.2.3+2.3.\left(4-1\right)+3.4.\left(5-2\right)+...+2018.2019.\left(2020-2017\right)\)
\(3B=1.2.3+2.3.4-1.2.3+...+2018.2019.2020-2017.2018.2019\)
\(3B=2018.2019.2020\)
\(B=\frac{2018.2019.2020}{3}\)
\(B=2743390280\)
Chúc bạn học tốt ~

\(A=1+3+3^2+3^3+...+3^{20}\)
\(\Rightarrow3A=3+3^2+3^3+...+3^{21}\)
\(\Rightarrow3A-A=\left(3+3^2+3^3+...+3^{21}\right)-\left(1+3+3^2+3^3+...+3^{20}\right)\)
\(\Rightarrow2A=3^{21}-1\)
\(\Rightarrow A=\frac{3^{21}-1}{2}=\frac{3^{21}}{2}-\frac{1}{2}\)
Ta lại có:
\(B=\frac{3^{21}}{2}\)
\(\Rightarrow B-A=\left(\frac{3^{21}}{2}-\frac{1}{2}\right)-\frac{3^{21}}{2}=\frac{1}{2}\)

0,006dam2 = 60 dm2.
0,07m2 = 700 cm2.
0,67m2 = 67 dm2.
1m2 = 0,01 dam2.
1m2 = 0,000001 km2.
1 tấn 20g = 1000,02 kg.
0,006dam2= 60 dm2
0,07m2 = 700 cm2
0,67m2 = 67 dm2
1m2 = 0,01 dam2
1m2 = 0,000001 km2.
1 tấn 20g = 1000,02 kg

a) 1 - 2 + 3 - 4 + 5 - 6 + .....+ 25 - 26
= (1 - 2) + (3 - 4) + (5 - 6) + .....+ (25 - 26)
= -1 + (-1) + ( -1 ) +...+ ( -1 ) {có 13 số )
= -13
b) tương tự nhé bn
\(A=1+2+2^2+...+2^{2018}\)
\(2A=2+2^3+2^4+...+2^{2019}\)
\(A=2A-A=1-2^{2019}\)
\(B-A=2^{2019}-\left(1-2^{2019}\right)\)
\(B-A=2^{2019}-1+2^{2019}\)
\(B-A=1\)
`#3107`
\(A=1+2+2^2+2^3+...+2^{2018}\) và \(B=2^{2019}\)
Ta có:
\(A=1+2+2^2+2^3+...+2^{2018}\)
\(2A=2+2^2+2^3+...+2^{2019}\)
\(2A-A=\left(2+2^2+2^3+...+2^{2019}\right)-\left(1+2+2^2+2^3+...+2^{2018}\right)\)
\(A=2+2^2+2^3+...+2^{2019}-1-2-2^2-2^3-...-2^{2018}\)
\(A=2^{2019}-1\)
Vậy, \(A=2^{2019}-1\)
Ta có:
\(B-A=2^{2019}-2^{2019}+1=1\)
Vậy, `B - A = 1.`