
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.


Mình làm một câu để bạn tham khảo, sau đó bạn áp dụng làm các bài còn lại nha ^^
Có gì không hiểu bạn ib nha ^^
1. \(2x=3y-2x\left(1\right)\) và \(x+y=14\)
\(\left(1\right)\Leftrightarrow4x=3y\)
\(\Leftrightarrow\dfrac{x}{3}=\dfrac{y}{4}\)
Theo tính chất dãy tỉ số bằng nhau, có:
\(\dfrac{x}{3}=\dfrac{y}{4}=\dfrac{x+y}{3+4}=\dfrac{14}{7}=2\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=2.3=6\\y=2.4=8\end{matrix}\right.\)
Bạn tự kết luận ^^

Ta có :
\(3x=4y=5z\)
\(\Rightarrow\dfrac{x}{\dfrac{1}{3}}=\dfrac{2y}{\dfrac{1}{2}}=\dfrac{3z}{\dfrac{3}{5}}=\dfrac{x+2y-3z}{\dfrac{1}{3}+\dfrac{1}{2}-\dfrac{3}{5}}=\dfrac{28}{\dfrac{7}{30}}=\dfrac{28.30}{7}=120\) \(\left(x+2y-3z=28\right)\)
\(\Rightarrow\left\{{}\begin{matrix}x=\dfrac{1}{3}.120=40\\y=\dfrac{1}{4}.120=30\\z=\dfrac{1}{5}.120=24\end{matrix}\right.\)

\(\frac{4\left(3x-2y\right)}{16}=\frac{3\left(2z-4x\right)}{9}=\frac{2\left(4y-3z\right)}{4}=\frac{12x-8y+6z-12x+8y-6z}{16+9+4}=\frac{0}{29}=0\)
\(\Leftrightarrow3x-2y=0\Leftrightarrow\frac{x}{2}=\frac{y}{3}\)
\(\Leftrightarrow2z-4x=0\Leftrightarrow\frac{x}{2}=\frac{z}{4}\)
\(\Leftrightarrow\frac{x}{2}=\frac{y}{3}=\frac{z}{4}\)
\(\Leftrightarrow\frac{x}{2}=\frac{y}{3}=\frac{z}{4}=\frac{2x+4y+5z}{4+12+20}=\frac{8}{36}=\frac{2}{9}=\frac{2x+3y-z}{4+12-4}\)=> A= 2x+3y -z = 12.2/9 =8/3

\(3x=2y\Rightarrow\frac{x}{2}=\frac{y}{3}\) ; \(4y=3z\Rightarrow\frac{y}{3}=\frac{z}{4}\)
\(\Rightarrow\frac{x}{2}=\frac{y}{3}=\frac{z}{4}\)
\(\Rightarrow\frac{x}{2}=\frac{2y}{6}=\frac{3z}{12}\)
Áp dụng tính chất của dãy tỉ số bằng nhau, ta có :
\(\frac{x}{2}=\frac{2y}{6}=\frac{3z}{12}=\frac{x+2y+3z}{2+6+12}=\frac{-20}{20}=-1\)
\(\Rightarrow x=-2;y=-3;z=-4\)

Xét \(\dfrac{x}{3}=\dfrac{y}{4}=\dfrac{z}{5}=k\)
\(\Rightarrow\left\{{}\begin{matrix}x=3k\\y=4k\\z=5k\end{matrix}\right.\) (1)
Thay (1) vào P
=> P = \(\dfrac{3k+2.4k+3.5k}{2.5k+3.4k+4.5k}+\dfrac{2.5k+3.4k+4.5k}{3.3k+4.4k+5.5k}\) + \(\dfrac{3.3k+4.4k+5.5k}{4.3k+5.4k+6.5k}\)
=> P = \(\dfrac{26k}{42k}+\dfrac{42k}{50k}\) + \(\dfrac{50k}{62k}\)
=> P = \(\dfrac{13}{21}+\dfrac{21}{25}+\dfrac{25}{31}\approx2,265499232\)

a: \(A=-4x^5y^3-2x^2y^3z^2-2y^4\)
b: \(B=-4x^5y^3-2x^2y^3z^2-2y^4+2x^2y^3z^2-\dfrac{2}{3}y^4+\dfrac{1}{5}x^4y^3=-4x^5y^3+\dfrac{1}{5}x^4y^3-\dfrac{8}{3}y^4\)