Question

[Karini]

Cho 2 đa thức: \(N\left(x\right)=-4x^4+9x^3-x^2+5x+\dfrac{1}{3}\)

                         \(M\left(x\right)=-x^4-9x^3+x^2+9x+\dfrac{4}{3}\)

a) Tính \(N\left(x\right)-M\left(x\right)\)

b) Tính \(M\left(x\right)+N\left(x\right)\)

Answer 1

[çá﹏๖ۣۜhⒺo╰‿╯²ᵏ⁹]

a) 

 \(\begin{matrix}N\left(x\right)=-4x^4+9x^3-x^2+5x+\dfrac{1}{3}\\^-M\left(x\right)=-x^4-9x^3+x^2+9x+\dfrac{4}{3}\\\overline{N\left(x\right)-M\left(x\right)=-3x^4+18x^3-2x^2-4x-1}\end{matrix}\)

b) 

   \(\begin{matrix}M\left(x\right)=-x^4-9x^3+x^2+9x+\dfrac{4}{3}\\^+N\left(x\right)=-4x^4+9x^3-x^2+5x+\dfrac{1}{3}\\\overline{M\left(x\right)+N\left(x\right)=-5x^4+14x+\dfrac{5}{3}}\end{matrix}\)