Question

[Vũ Thảo Anh]

cc giúp mk làm bài này với ,cảm ơn trước nhá

Answer 1

[Nguyễn Lê Phước Thịnh]

a: Ta có: \(K=\left(\dfrac{2+x}{2-x}+\dfrac{x}{2+x}-\dfrac{4x^2+2x+4}{x^2-4}\right):\left(\dfrac{x^2+9}{x^2-2x}-\dfrac{2x}{x-2}\right)\)

\(=\dfrac{-x^2-4x-4+x^2-2x-4x^2-2x-4}{\left(x-2\right)\left(x+2\right)}:\dfrac{x^2+9-2x^2}{x\left(x-2\right)}\)

\(=\dfrac{-4x^2-8x-8}{\left(x-2\right)\left(x+2\right)}\cdot\dfrac{x\left(x-2\right)}{-x^2+9}\)

\(=\dfrac{-4\left(x^2+2x+1\right)}{x+2}\cdot\dfrac{x}{-\left(x-3\right)\left(x+3\right)}\)

\(=\dfrac{-4x\left(x+1\right)^2}{-\left(x-3\right)\left(x+3\right)\left(x+2\right)}\)