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a) ( - 6,37 x 0,4 ) x 2,5
=-6,37 x (0,4 x 2,5)
=-6,37 x 1
=-6,37
b) ( -0,125 ) x ( -5,3 ) x 8
=(-0,125 x 8) x (-5,3)
=-1 x (-5,3)
=5,3
c) ( -2,5 ) x ( -4 ) x ( -7,9 )
=[(-2,5) x (-4)] x (-7,9)
=10 x (-7,9)
=-79
a)(-6,37x0,4)x2,5=-6,37x(0,4x2,5)=-6,37x1=-6,37
b)(-0,125)x(-5,3)x8=(-0,125x8)x(-5,3)=-1x(-5,3)=5,3
c)(-2,5)x(-4)x(-7,9)=[(-2,5)x(-4)]x(-7,9)=10x(-7,9)=-79
a)
\(\left(-6,37.0,4\right)2,5=\left(-6,37\right).\left(\frac{2}{5}.\frac{5}{2}\right)=1.\left(-6,37\right)=-6,37\)
b)
\(\left(-0,125\right)\left(-5,3\right).8=\left[\left(-\frac{1}{8}\right).8\right]\left(-5,3\right)=\left(-1\right)\left(-5,3\right)=5,3\)
c)
\(\left(-2,5\right).\left(-4\right).\left(-7,9\right)=\left[\left(-\frac{5}{2}\right).\left(-4\right)\right]\left(-7,9\right)=10.\left(-7,9\right)=-79\)
d)
\(\left(-0,375\right).4\frac{1}{3}.\left(-2\right)^3=\left(-\frac{3}{8}\right).\frac{12}{3}.\left(-8\right)=12\)
a) (- 6,37 . 0,4) . 2,5
= -6,37 . (0,4 . 2,5)
= -6,37 . 1
= -6,37
b) (-0,125 ) . (-5,3) . 8
= ( - 0,125 . 8) . (-5,3)
= -1 . ( -5,3)
= 5,3
c) ( -2,5) . (-4) . (-7,9)
= ( -2,5 . -4) . (-7,9)
= 10 . (-7,9)
= -79
\(a,\frac{8^{12}.5^{21}}{2^{17}.10^{19}}=\frac{\left(2^3\right)^{12}.5^{21}}{2^{17}.2^{19}.5^{19}}=\frac{2^{36}.5^{21}}{2^{36}.5^{19}}=25\)
\(b,\left(x-5\right).\left(x+\frac{1}{2}\right)=0\)
\(\Rightarrow x-5=0\)hoặc \(x+\frac{1}{2}=0\)
\(x=5\)hoặc \(x=-\frac{1}{2}\)
\(c,\left|x-6\right|-\frac{1}{2}=\frac{3}{2}\)
\(\left|x-6\right|=2\)
\(\Rightarrow x-6=2\)hoặc \(x-6=-2\)
\(x=8\)hoặc \(x=4\)
\(\frac{x}{-\frac{3}{5}}=\frac{-10}{21}\)
\(\Leftrightarrow21x=-10\cdot\frac{-3}{5}\)
\(\Leftrightarrow21x=6\Leftrightarrow x=\frac{2}{7}\)
\(\frac{x}{\frac{41}{3}}=-25\)
\(\Leftrightarrow x=-25\cdot\frac{41}{3}=\frac{-1025}{3}\)
3.Đề sao thế nhỉ???